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Nana76 [90]
3 years ago
9

Your bedroom wall is 171 inches wide. You want to hang two posters, each 42 inches across, with an equal space between each post

er and the wall edges.
How many inches of space should you leave between the wall edge and each poster?
Mathematics
1 answer:
Readme [11.4K]3 years ago
3 0
Your answer should be 29
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One side of triangle is 4cm longer than the shortest side and 2cm shorter than the longest side the perimeter is 38cm what are t
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Determine whether the ffunction X/(x^2-1) is odd even or neither
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equation is:

f(x) = \frac{x}{ {x}^{2} - 1 }

so if its even f(-x) should be equal to f(x)

that means

f( - x) =   \frac{ - x}{  {( - x)}^{2}  - 1}  \\  \\ f( - x) =     - \frac{ x}{ {x}^{2}  - 1}

so f(x) is not equal to f(-x) so its not even

If its odd than f(-x) should be equal to -f(x)

- f(x) =  - ( \frac{ x}{ { x}^{2} - 1 } ) \\  - f(x) =    - \frac{ x}{ {x}^{2} - 1 }

so as we can see f(-x)= - f(x)

so the function is odd

Ans:function is odd and not even

3 0
3 years ago
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2 years ago
You have 400 feet of fencing to enclose a rectangular plot. Find the length and width of the plot that will maximize the area. W
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Well, we can denote L and W for the length and width respectively. Lets say the A is the area, we have: 1. A=(L × W) as well as 2. 2(L+W)=400. We rearrange the second equation to get 3. W=200-L. From this, we can see that 0<L<200. Substitute the third equation into the first to get A=(200L-L²). put this formula into the scientific calculator and you will find a parabola with a maximum. That would be the maximum area of the enclosed area. Alternatively, we can say that L is between 0 and 200 when the area equals 0. (The graph you find will be  area against length). As the maximum is generally found halfway, we substitute 100 into the equation and we end up with 10000.

Hope this helps.
6 0
3 years ago
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