Answer:
Step-by-step explanation:
Answer:
C. y₂ = (1 + (t/n))²
Step-by-step explanation:
yₙ₊₁ = yₙ + Δt F(tₙ, yₙ)
yₙ₊₁ = yₙ + Δt yₙ
yₙ₊₁ = yₙ + (t/n) yₙ
When n=0:
y₁ = y₀ + (t/n) y₀
y₁ = 1 + (t/n)
When n=1:
y₂ = y₁ + (t/n) y₁
y₂ = 1 + (t/n) + (t/n) (1 + (t/n))
y₂ = 1 + (t/n) + (t/n) + (t/n)²
y₂ = 1 + 2(t/n) + (t/n)²
y₂ = (1 + (t/n))²
Step-by-step explanation:
if you are given an equation of a form y=kx+b, k is gradient and b is y-intercept
in c you can write this equation as y=(2x/3)-2,so gradient = 2/3 and y-intercept =-2
in e:6y=2x+3
y=x/3+1/2,gradient = 1/3, y-intercept=1/2
Step-by-step explanation:
x =7y ----(1)
xy=252 ----(2)
(1) into (2):
(7y)(y) = 252
7y=15.874....
y=2.27
y value into (1)
x= 7(2.268)
x=15.87
the two numbers are 15.87 and 2.27 (Ans)
