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Crazy boy [7]
3 years ago
6

A sea lion dove from the water's surface at sea level to an altitude of −216.12 meters in 2.4 minutes.

Mathematics
2 answers:
dlinn [17]3 years ago
7 0

divide total distance by time

-216.12 / 2.4 = -90.05 meters per second

Valentin [98]3 years ago
4 0
Hello,


The answer to this problem is -90.05.


Hope this helps
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Solve this problem thanks
vovikov84 [41]

The three missing lengths are the left hypotenuse, x, the middle altitude, y, and the right hypotenuse, z.


9/y = y/16


y^2 = 9 * 16


y^2 = 144


y = 12


9^2 + 12^2 = x^2


x^2 = 225


x = 15


12^2 + 16^2 = z^2


z^2 = 400


z = 20


From left to right, the sides measure 15, 12, and 20 units.

5 0
3 years ago
Read 2 more answers
Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)
Crazy boy [7]

Answer:

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Step-by-step explanation:

To find : Convert 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C} into \frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Solution :

We convert units one by one,

1\text{ m}^2=10.7639\text{ ft}^2

1\text{ sec}=\frac{1}{3600}\text{ hour}

1\text{ cal}=0.003968\text{ BTU}

Converting temperature unit,

^\circ C\times \frac{9}{5}+32=^\circ F

1^\circ C\times \frac{9}{5}+32=33.8^\circ F

So, 1^\circ C=33.8^\circ F

Substitute all the values in the unit conversion,

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Therefore, The conversion of unit is 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

3 0
3 years ago
Given sample set A= {1,2,3,4,5} how many items are in the complement of set B if set B= all numbers greater than 2? OPTIONS : 3
Ostrovityanka [42]

Answer:

2

Step-by-step explanation:

It sounds like we are pretending A is the universe.  The only numbers in our world are 1,2,3,4, and 5.

You are given B is all numbers greater than 2.

The complement of B would all the elements not listed in B.

The elements in B are 3,4, and 5, since we are looking for numbers greater than 2 in our world of numbers above.

The elements not in B are 1 and 2.

So B complement is {1,2}.

There are 2 elements in our set for B complement. The elements that were counted were just the element 1 and the element 2.

6 0
3 years ago
Given that x = 7, write an equation that contains two different equivalent expressions each including at least one variable (x)
inna [77]

Well here are two equivalent different expressions of my making that you could use for this question.

f(x) = 2x - 7
g(x) = 3x - 28 / 2

When x = 7, these two different expressions will equate to the same value of 7. If you meant something else let me know, otherwise this is what you should put for your essay-question.

3 0
3 years ago
Help me pleasee !!!!
Daniel [21]

Answer:

here (edit I made a mistake)

Step-by-step explanation:

9) y=\frac{3}{5} x +5

10) y = x - 3

11)  y=-\frac{3}{5} x - 3

12) y=\frac{5}{4} x + 2

these are the slop int forms, my bad...

sorry

3 0
2 years ago
Read 2 more answers
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