The way this problem is stated is that you put 1 grain of rice on the first square, the second square has 2 grains of rice. The third square has 4 grains of rice and you keep on doubling from there. When you tell me there is a 0 square, I'm not sure what you mean.
That would mean (to me) that square 1 has 2 grains of rice
Square 2 has 4 grains of rice
Square 3 has 8 grains of rice
The table goes up to 64 squares on a chess board.
2^64 which is (rounded) to about 1.84 with 17 zeros behind the 1.84.
My calculator says the answer is 1.84 * 10^19
I think you want
2^64<<<<<answer.
Or maybe
y =R(x) = 2^x <<<< answer.
where the domain is 0 <=x <= 64 contained in the integers.
Answer:
Step-by-step explanation:
Use the given functions to set up and simplify 
The point in the middle between 3G and 3 is a multiplication sign btw
Okay so you have to start by working out how many times you multiply 5 by itself to get 125.
5x5x5=125
therefore: (5^3)^2x) is the answer:)
<span>B) (1, 5) is your best answer
B (0,6) creates the top of the kite
D (0,2) creates the bottom
A (-1,5) creates the left side of the kite
D (1,5) creates the right side (only the x is flipped, because has congruent sides of both the top, and both the bottom.
hope this helps</span>
Answer:
B
Step-by-step explanation:
To rationalise the denominator.
Multiply the numerator/denominator by the radical on the denominator.
The radical on the denominator is 
, thus
Multiply the fraction by
→ B
