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3 years ago

Help!!!!

Mathematics

1 answer:

ipn [44]3 years ago

4 0

Answer:

The answer to your question is: letter A

Step-by-step explanation:

See the picture below

When we divide the polynomial by the factor the result is zero, that's why letter A is the factor.

When we divide the polynomial by B, C or D the residue is not zero, then they are not factors.

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aleksandrvk [35]

Answer:

16 feet

Step-by-step explanation:

This ladder and building creates a right triangle with 34 as the hypotenuse and 30 as a side. the Pythagorean theorem says that a^2 + b^2 = c^2 so 900 + b^2 = 1156. b^2 = 256, square root both sides and you get b = 16

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3 years ago

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2 years ago

Now let the figure show a scale drawing of a park with the largest dimension equal to 63 meters. What is the scale?

r-ruslan [8.4K]

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If the coordinates of the endpoints of a diameter of the circle are known, the equation of a circle can be found. first, find

Alja [10]

Given

Endpoints of the diameter (5,2) and (-7,4)

Step One

Find the center

Center = (x2 + x1)/2 , (y2 + y1)/2

x2 = -7; x1 = 5; y2 = 4; y1 = 2

Center = (-7 + 5)/2 ; (4 + 2)/2;

Center = (-1 , 3)

Step Two

Find the radius squared using the distance formula. Use (5,2) as the second point. The other point is the center.

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4 0

3 years ago

On a snow day, Mason created two snowmen in his backyard. Snowman A was built to a height of 51 inches and Snowman B was built t

mr_godi [17]

Answer:

A ( t ) = -4t + 51

B ( t ) = -2t + 29

t < 11 hours ... [ 0 , 11 ]

Step-by-step explanation:

Given:-

- The height of snowman A, Ao = 51 in

- The height of snowman B, Bo = 29 in

Solution:-

- The day Mason made two snowmans ( A and B ) with their respective heights ( A(t) and B(t) ) will be considered as the initial value of the following ordinary differential equation.

- To construct two first order Linear ODEs we will consider the rate of change in heights of each snowman from the following day.

- The rate of change of snowman A's height ( A ) is:

$\frac{d h_a}{dt} = -4$

- The rate of change of snowman B's height ( B ) is:

$\frac{d h_b}{dt} = -2$

Where,

t: The time in hours from the start of melting process.

- We will separate the variables and integrate both of the ODEs as follows:

$\int {} \, dA= -4 * \int {} \, dt + c\\\\A ( t ) = -4t + c$

$\int {} \, dB= -2 * \int {} \, dt + c\\\\B ( t ) = -2t + c$

- Evaluate the constant of integration ( c ) for each solution to ODE using the initial values given: A ( 0 ) = Ao = 51 in and B ( 0 ) = Bo = 29 in:

$A ( 0 ) = -4(0) + c = 51\\\\c = 51$

$B ( 0 ) = -2(0) + c = 29\\\\c = 29$

- The solution to the differential equations are as follows:

A ( t ) = -4t + 51

B ( t ) = -2t + 29

- To determine the time domain over which the snowman A height A ( t ) is greater than snowman B height B ( t ). We will set up an inequality as follows:

A ( t ) > B ( t )

-4t + 51 > -2t + 29

2t < 22

t < 11 hours

- The time domain over which snowman A' height is greater than snowman B' height is given by the following notation:

Answer: [ 0 , 11 ]

8 0

2 years ago