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uranmaximum [27]
3 years ago
13

A parallelogram with sides of 6 and 10 has an area of 30. Find the measure of the small angle of the parallelogram.

Mathematics
1 answer:
dmitriy555 [2]3 years ago
4 0
<span>A = 2 * (0.5ab) + b (10 - a) = ab + 10b - ab = 10b 

10b = 30√2; b = 3√2 

sin α = 3√2 / 6; α = 45 degrees 

Small angle: 45°; Large angle: 135°</span><span>
</span>
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scZoUnD [109]

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I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
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In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
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