Question

A parallelogram with sides of 6 and 10 has an area of 30. Find the measure of the small angle of the parallelogram.

Answer 1

A = 2 * (0.5ab) + b (10 - a) = ab + 10b - ab = 10b 

10b = 30√2; b = 3√2 

sin α = 3√2 / 6; α = 45 degrees 

Small angle: 45°; Large angle: 135°