3 years ago

A parallelogram with sides of 6 and 10 has an area of 30. Find the measure of the small angle of the parallelogram.

1 answer:

4 0

A = 2 * (0.5ab) + b (10 - a) = ab + 10b - ab = 10b

10b = 30√2; b = 3√2

sin α = 3√2 / 6; α = 45 degrees

Small angle: 45°; Large angle: 135°

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Margarita [4]

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see the attached figure to better understand the problem

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