Let and be the amounts of available alloy (AA) and pure magic steel that are used, so we also have
DA13 is supposed to contain 7% gold, 3% silver, and 90% steel, so that 2.7 kg of it is made up of
For each kg of the available alloy (AA), there is a contribution of 0.21 kg of gold, 0.09 kg of silver, and therefore 0.70 kg of steel; kg of it will contain kg of gold, kg of silver, and kg of steel. Each kg of magic steel of course contributes 1 kg of steel; kg of it will contribute kg of steel.
Then the dwarves need
• total gold:
• total silver:
• total steel:
Solve for and . The first two equations are consistent and give , and substituting this into the third we find . So the dwarves must combine 0.90 kg of AA and 1.80 kg of magic steel.
Exact form is 469/12 decimal form is 39.083 repeating and mixed number form is 39/1/12
500/6.7=74.6268.....
500 miles/6.7 hours : 74.63 miles/1 hour
The average speed of the car was 74.63 miles/hour
The height of the hawk flying over the tree is 462.14 feet
<h3>How to find the height of the hawk using angle of elevation?</h3>
The observer (O) is located 660 feet from a tree (T).
The observer notices a hawk (H) flying at a 35° angle of elevation from his line of sight.
The situation forms a right angle triangle.
Therefore, using trigonometric ratios,
tan ∅ = opposite / adjacent
where
- ∅ = angle of elevation
- opposite side = height of the hawk
- adjacent side = distance of the observer from the tree
Therefore,
tan 35 = h / 660
cross multiply
h = 660 tan 35
h = 660 × 0.70020753821
h = 462.136975218
h = 462.14 feet
Therefore, the height of the hawk flying over the tree is 462.14 feet.
learn more on angle of elevation here: brainly.com/question/6286482
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