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UkoKoshka [18]
3 years ago
7

El productor del números es 28. Sabiendo que el primer número es 3 unidades menor que el segundo, calcula los dos número

Mathematics
1 answer:
Rasek [7]3 years ago
8 0

Answer:

Tienes 3 números, "x", "y", "z"

=> El primero es 20 unidades menor que el segundo:

El primero es "x", y el segundo es "y", entonces:

x = y - 20

=> El tercero es igual a la suma de los dos primeros:

El tercero es "z", entonces:

z = x + y

z = (y - 20) + y

z =  2y - 20

=> Entre los tres suman 120

x + y + z = 120

y - 20 + y + 2y - 20 = 120

4y - 40 = 120

4y = 160

y = 40

Si y = 40, entonces:

x = y - 20

x = 20

Además, z = 2y - 20

z= 60

RPTA:

x=20

y=40

z=60

Step-by-step explanation:

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Answer:

The Proof and Explanation  for

Part C ,

Qs 9 and

Qs 10  are below.

Step-by-step explanation:

PART C .

Given:

AD || BC ,

To Prove:

ΔAED ≅ ΔCEB

Proof:

Statement                             Reason

1. AD || BC                           1. Given

2. ∠A ≅ ∠C                        2. Alternate Angles Theorem as AD || BC

3. ∠AED ≅ ∠CEB               3. Vertical Opposite Angle Theorem.

4. AE ≅ EC                         4. Given

5. ΔAED ≅ ΔCEB               5. By A-S-A congruence test....Proved

Qs 9)

Given:

AB ≅ BC ,

∠ABD ≅ ∠CBD

To Prove:

∠A ≅ ∠C

Proof:

Statement                             Reason

1. ∠ABD ≅ ∠CBD              1. Given

2. AB ≅ CB                       2. Given      

3. BD ≅ BD                       3. Reflexive Property

4. ΔABD ≅ ΔCBD             4. By S-A-S congruence test

5. ∠A ≅ ∠C                       5. Corresponding parts of congruent Triangles Proved.

Qs 10)

Given:

∠MCI ≅ ∠AIC

MC ≅ AI

To Prove:

ΔMCI ≅ ΔAIC

Proof:

Statement                             Reason

1. ∠MCI ≅ ∠AIC       1. Given

2. MC ≅ AI              2. Given

3. CI ≅ CI                3. Reflexive Property

4. ΔMCI ≅ ΔAIC     4. By S-A-S congruence test

3 0
3 years ago
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