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3 years ago

El productor del números es 28. Sabiendo que el primer número es 3 unidades menor que el segundo, calcula los dos número

Mathematics

1 answer:

Rasek [7]3 years ago

8 0

Answer:

Tienes 3 números, "x", "y", "z"

=> El primero es 20 unidades menor que el segundo:

El primero es "x", y el segundo es "y", entonces:

x = y - 20

=> El tercero es igual a la suma de los dos primeros:

El tercero es "z", entonces:

z = x + y

z = (y - 20) + y

z = 2y - 20

=> Entre los tres suman 120

x + y + z = 120

y - 20 + y + 2y - 20 = 120

4y - 40 = 120

4y = 160

y = 40

Si y = 40, entonces:

x = y - 20

x = 20

Además, z = 2y - 20

z= 60

RPTA:

x=20

y=40

z=60

Step-by-step explanation:

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2n + 1.6 = 17.6 what is the value of n?

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Answer:

Step-by-step explanation:

2n + 1.6 = 17.6 what is the value of n?

2n + 1.6 = 17.6

2n = 17.6 - 1.6

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-----------------

check

2n + 1.6 = 17.6

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Step-by-step explanation:

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A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while

ki77a [65]

Answer:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=12$ represent the population standard deviation

n represent the sample size

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is $\alpha=1-0.96 =0.04$ . And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got $z_{\alpha/2}=2.054$ , replacing into formula (b) we got:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

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