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laiz [17]
3 years ago
11

What is the least common factor of 11 and 15

Mathematics
1 answer:
jeyben [28]3 years ago
6 0

Answer:

165

Step-by-step explanation

One way to find the least common multiple of two numbers is to first list the prime factors of each number. Then multiply each factor the most number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.

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Nick decided to take 2/5 of the money in his bank account and donate it to a local charity. If nick donated $70 to a local chari
S_A_V [24]

Answer:

<u> The total amount = $175</u>

Step-by-step explanation:

Let the total amount in his bank account = x

Nick decided to take 2/5 of the money in his bank account and donate it to a local charity

So, he donates with \frac{2}{5} x

If nick donated $70 to a local charity

so, \frac{2}{5} x = 70

solve for x

∴ x = 5*70/2 = 350/2 = $175

<u>So, The total amount = $175</u>

3 0
3 years ago
(Free points)<br><br>Factorise x³ + 216y³ + 8z³ - 36xyz​
Nadusha1986 [10]

Answer:

[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]

Step-by-step explanation:

x³+216y³+8z³-36xyz

x³+(6y)³+(2z)³-3×6×2×xyz

As we know

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)

Let a=x

b=6y

c=2z

Now.

[x+6y+2z][(x²+(6y)²+(2z)²-x×6y-6y×2z-x×2z]

[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]

3 0
3 years ago
Read 2 more answers
I need help now its due right now can anyone help me
cestrela7 [59]

Answer:

(2,-3)

Step-by-step explanation:

I thought you'd actually have to calculate it but I guess they just wanted to give you guys a graph lol

7 0
3 years ago
Solve for z −cz+6z=tz+83
Alborosie

Answer: z=83/c - 7 + t

Step-by-step explanation:

6 0
3 years ago
H/3+h/6=1 how many hours will it take them to mow their lawn a.6 b.3 c.2 d.1
Furkat [3]

Answer:

c 2

Step-by-step explanation:

h/3 + h/6 =1

Multiply both sides by 6 to eliminate the fractions

6(h/3+h/6) = 1*6

2h +h =6

Combine like terms

3h = 6

Divide by 3

3h/3 = 6/3

h =2

2 hours

8 0
3 years ago
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