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Delicious77 [7]
3 years ago
14

How to solve step by step [(7,5-1,5) x 10^-11]^2 ??

Mathematics
1 answer:
Oliga [24]3 years ago
5 0
1.7,5-1,5=6
2.10-11=-1
3.6×-1=-6
4.-6+2=-4
You might be interested in
List the following in order from least to greatest<br><br> -3/5, -0.4, -1, -0.5
nikklg [1K]

-1

- 3/5

- 0.5

-0.4

The least is always the one furthest away from 0

5 0
3 years ago
If two thirds of a number is 56, what is three-quarters of that number?
Crank

Answer:

84

Step-by-step explanation:

56/2 = 28

28 x 3 = 84

To check work: 84/3 =28

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B
riadik2000 [5.3K]

Let

S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n

where we assume |r| < 1. Multiplying on both sides by r gives

r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}

and subtracting this from S_n gives

(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}

As n → ∞, the exponential term will converge to 0, and the partial sums S_n will converge to

\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}

Now, we're given

a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a

a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}

We must have |r| < 1 since both sums converge, so

\dfrac{15}a = \dfrac1{1-r}

\dfrac{150}{a^2} = \dfrac1{1-r^2}

Solving for r by substitution, we have

\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)

\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}

Recalling the difference of squares identity, we have

\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}

We've already confirmed r ≠ 1, so we can simplify this to

\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15

It follows that

\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12

and so the sum we want is

ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

7 0
2 years ago
ASAP NEED HELP!!!! ∩ω∩ Michael has $15 and wants to buy a combination of school lunches to feed at least three classmates. A san
Nikitich [7]

Answer:

Step-by-step explanation:

A. The first inequality is graphed as a shaded area below the solid line with x-and y-intercepts of 7.5 and 5, respectively. The second inequality is graphed as a shaded area above the solid line with x- and y-intercepts of 3.

The solution set is the set of integer-valued grid points one or between the lines.

__

B. The point (5, 1) is included in the solution area. Mathematically, it can be shown to satisfy the two inequalities:

  2(5) +3(1) ≤ 15   ⇒   13 ≤ 15   True

  (5) +(1) ≥ 3   ⇒   6 ≥ 3   True

__

C. The point (5, 1) is in the solution set. It means Michael can purchase 5 sandwiches and 1 hot lunch within his budget constraints. That will provide 6 meals, which is more than the minimum of 3 that he wants to provide.

8 0
3 years ago
What subtracted by 26 equals -102​
Lesechka [4]

Answer:

-76

Step-by-step explanation:

6 0
2 years ago
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