Answer:
There are 15 problems worth 2 points and there are 10 problems worth 3 points
Step-by-step explanation:
To realize this problem we will perform two equations
one will represent the number of problems and another the number of points
x would be the number of problems worth 2 points and y the amount worth 3 points
x + y = 25
(x * 2) + (y * 3) = 60
we clear the x of the first equation
x + y = 25
x = 25 - y
and replace the x with (25 - y) in the second equation
(x * 2) + (y * 3) = 60
( (25 - y) * 2) + (y * 3) = 60
50 - 2y + 3y = 60
-2y + 3y = 60 - 50
y = 10
Now we return to the first equation and replace y with 10
x = 25 - y
x = 25 - 10
x = 15
