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kompoz [17]
3 years ago
9

Suppose the average commute time of your employees is unknown. The standard deviation of their commute time is estimated as 22.8

minutes. How many employees must be included in a sample to create a 99 percent confidence interval for the average commute time with a confidence interval width of no more than 12 minutes
Mathematics
1 answer:
nexus9112 [7]3 years ago
6 0

Answer:

96 employees

Step-by-step explanation:

Given that the standard deviation = 22.8

The width in the question = 12

We solve for the margin of error E.

E = width / 2

= 12/2 = 6

At 99%

Alpha = 1-0.99

= 0.01

Alpha/2 = 0.01/2 = 0.005

Z0.005 = 2.576

Sample size n

= ((2.576x22.8)/2)²

= 95.8

= 96

The number of employees is 96

Thank you!

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den301095 [7]

Answer:

37

Step-by-step explanation:

Highest - lowest = range

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4 0
2 years ago
I need #2, #3, #4, #7, and #8.<br> but do as much as you can pls thanks !
kifflom [539]

Answer:

See explanation.

Step-by-step explanation:

2) Your written answer is correct, y = x +4

3) Slope of perpendicular line: 5/2

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4 = (5/2)(4) + b

4 = 10 + b

b = -6

So, y=(5/2)x - 6

4) Slope of perpendicular line: 1

y=mx+b

5 = (1)(4) + b

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So, y = x + 1

7) Slope of perpendicular line: 3/4

y=mx+b

4 = (3/4)(4) + b

4 = 3 + b

b = 1

So, y = (3/4)x + 1

8) Slope of perpendicular line: 1/4

y=mx+b

-2 = (1/4)(0) + b

b = -2

So, y = (1/4)x - 2

4 0
3 years ago
Idk this pls help don’t understand.
lawyer [7]

Answer: 60, but I got other answers to but 60 was my first.

sorry if wrong.

Step-by-step explanation:

7 0
2 years ago
The product of 7/16,4/3, and 1/2 is
Lady_Fox [76]
The answer would be 7/24.
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