All categories

2 years ago

Someone please help me

Mathematics

1 answer:

natka813 [3]2 years ago

3 0

Answer:

I would say ray but im not 100% sure.

Step-by-step explanation:

You might be interested in

Solve for x. Round to the nearest tenth, if necessary.

blsea [12.9K]

Answer:

ST = x = 1.8 (to the nearest tenth)

Step-by-step explanation:

STU is a right triangle right angled at T with S =61° and hypotenuse SU=3.7 units.

ST = x = SUcos(61°) = 3.7cos(61°) = 3.7*0.48481 = 1.7938

6 0

3 years ago

Read 2 more answers

5×67-34÷2+5 equals what

bekas [8.4K]

Answer: $323$

Step-by-step explanation:

1) Add () to the equation: $(5*67)-(34/2)+5$

2) Multiply: $5*67=335$

3) Divide: $34/2=17$

4) Subtract: $335-17=318$

5) Add: $318+5=323$

3 0

2 years ago

Read 2 more answers

Point R is located at (-9,8) and point T is located at (-9,-7) on a coordinate plane.

poizon [28]

Answer:

15 unit

Step-by-step explanation:

Applying

/RT/ = √[(y₂-y₁)²+(x₂-x₁)²]............. Equation 1

Where /RT/ = distance between point R and Point T

From the question,

Given: y₁ = -9, x₁ = 8, y₂ = -9, x₂ = -7

Substitute these values into equation 1

/RT/ = √[(-9-(-9))²+(-7-8)²]

/RT/ = √[(0)²+(-15)²]

/RT/ = √225

/RT/ = 15 unit

Hence the distance between point R and point T is 15 unit

3 0

2 years ago

you deposited $5500 in a account that pays 3.6% annual interest. find the balance after 2 years if the interest is compound mont

Sedaia [141]

Answer:

$5,909.97

Step-by-step explanation:

We will use the compound interest formula for this problem as shown below:

$A=P(1+\frac{r}{n} )^{nt}$

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, change 3.6% into a decimal:

3.6% -> $\frac{3.6}{100}$ -> 0.036

Now plug in the values:

$A=5,500(1+\frac{0.036}{12})^{12(2)}$

$A=5,909.97$

After 2 years, the balance would be $5,909.97

6 0

3 years ago

Four integers are consecutive terms of an arithmetic sequence. The sum of these four numbers is 24 and the product is 945.Find t

Marta_Voda [28]

When common difference, $d=\sqrt{39}$ then the largest term of these four terms will be $6+3\sqrt{39}$

Let four consecutive terms of AP is,

$a-3d, a-d, a+d, a+3d$

Since, sum of all four terms is 24

So, $a-3d+a-d+a+d+a+3d=24\\\\a=6$

And product is 945

So, $(a-3d)(a+3d)(a-d)(a+d)=945\\\\9d^4-360d^2+351=0\\\\d^4-40d^2+39=0\\\\(d^2-1)(d^2-39)=0\\\\d=1,-1\\d=\sqrt{39}, -\sqrt{39}$

When d= 1, -1 then largest term is 9

When $d=\sqrt{39}, -\sqrt{39}$ then largest term is $6+3\sqrt{39}$

Learn more:

https://brainly.in/question/3719232

7 0

2 years ago