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kupik [55]
2 years ago
11

Someone please help me

Mathematics
1 answer:
natka813 [3]2 years ago
3 0

Answer:

I would say ray but im not 100% sure.

Step-by-step explanation:

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Solve for x. Round to the nearest tenth, if necessary.
blsea [12.9K]

Answer:

ST = x = 1.8 (to the nearest tenth)

Step-by-step explanation:

STU is a right triangle right angled at T with S =61° and hypotenuse SU=3.7 units.

ST = x = SUcos(61°) = 3.7cos(61°) = 3.7*0.48481 = 1.7938

6 0
3 years ago
Read 2 more answers
5×67-34÷2+5 equals what
bekas [8.4K]

Answer: 323

Step-by-step explanation:

1) Add () to the equation: (5*67)-(34/2)+5

2) Multiply: 5*67=335

3) Divide: 34/2=17

4) Subtract: 335-17=318

5) Add: 318+5=323

3 0
2 years ago
Read 2 more answers
Point R is located at (-9,8) and point T is located at (-9,-7) on a coordinate plane.
poizon [28]

Answer:

15 unit

Step-by-step explanation:

Applying

/RT/ = √[(y₂-y₁)²+(x₂-x₁)²]............. Equation 1

Where /RT/ = distance between point R and Point T

From the question,

Given: y₁ = -9, x₁ = 8, y₂ = -9, x₂ = -7

Substitute these values into equation 1

/RT/ = √[(-9-(-9))²+(-7-8)²]

/RT/ = √[(0)²+(-15)²]

/RT/ = √225

/RT/ = 15 unit

Hence the distance between point R and point T is 15 unit

3 0
2 years ago
you deposited $5500 in a account that pays 3.6% annual interest. find the balance after 2 years if the interest is compound mont
Sedaia [141]

Answer:

$5,909.97

Step-by-step explanation:

We will use the compound interest formula for this problem as shown below:

A=P(1+\frac{r}{n} )^{nt}

<em>P = initial balance</em>

<em>r = interest rate (decimal)</em>

<em>n = number of times compounded annually</em>

<em>t = time</em>

<em />

First, change 3.6% into a decimal:

3.6% -> \frac{3.6}{100} -> 0.036

Now plug in the values:

A=5,500(1+\frac{0.036}{12})^{12(2)}

A=5,909.97

After 2 years, the balance would be $5,909.97

6 0
3 years ago
Four integers are consecutive terms of an arithmetic sequence. The sum of these four numbers is 24 and the product is 945.Find t
Marta_Voda [28]

When common difference, d=\sqrt{39} then the largest term of these four terms will be 6+3\sqrt{39}

Let four consecutive terms of AP is,

     a-3d, a-d, a+d, a+3d

Since, sum of all four terms is 24

So,   a-3d+a-d+a+d+a+3d=24\\\\a=6

And product is 945

So,  (a-3d)(a+3d)(a-d)(a+d)=945\\\\9d^4-360d^2+351=0\\\\d^4-40d^2+39=0\\\\(d^2-1)(d^2-39)=0\\\\d=1,-1\\d=\sqrt{39}, -\sqrt{39}

When d= 1, -1 then largest term is 9

When d=\sqrt{39}, -\sqrt{39} then largest term is 6+3\sqrt{39}

Learn more:

https://brainly.in/question/3719232

7 0
2 years ago
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