Answer:
I. 6x2 + 25x + 24 = 0 6x2 + 16x + 9x + 24 = 0 2x (3x +8) + 3 (3x + 8) = 0 (2x + 3) (3x +8) ... < y=1; = x<y I. 10x2 + 33x + 27 = 0 => 10x2 + 15x + 18x + 27 = 0 => 5x (2x + 3) + 9 (2x + 3) = 0 => (5x +9) (2x +3) ... x = —9/5, –3/2 II. ... (b) 62 (d) is TX TX II.
To solve for s all you have to do is factor the 7 and simplify the rest.
7s-21=21
7s=42
s=6
5914 1404 393
Answer:
A) 1.3×10^37 ergs
B) 1.435×10^3 mm
Step-by-step explanation:
A) The amount of energy will be the product of the energy rate and time:
(3.9×10^33 ergs/s)×(3.25×10^3 s) =12.675×10^(33+3) ergs
= 1.2675×10^(1+36) ergs
= 1.2675×10^37 ergs ≈ 1.3×10^37 ergs
The mantissa of the result is the product 3.9×3.25, adjusted to have one digit left of the decimal point. The exponent of the result is the sum of the exponents of the factors, adjusted by 1 to match the adjustment in the mantissa.
The final value should be rounded to 2 significant figures, reflecting the precision of the sun's energy production.
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B) A millimeter is a small fraction of an inch. 10^-3 mm is a small fraction of the width of a human hair, so 1.435×10^-3 mm is not a reasonable estimate of the distance between railroad tracks.
On the other hand, 1.435×10^3 mm is 1.435 m, almost 56.5 inches. This is a much more reasonable measurement of the distance between railroad rails.
1.435×10^3 mm is more reasonable
2473.14286 is the answer. U do 6 times 2876 which is 17256. Then divide by 7 which is 2465.14286. Then add 8 which is <span>2473.14286</span>
