<h3>
Answer: 10^(1/2)</h3>
When we use an exponent of 1/2, it is the same as a square root. The more general rule is
In this case, we plug in x = 10.
The use of a fractional exponent is handy when you want to deal with things like cube roots on a calculator. This is because
![\sqrt[3]{x} = x^{1/3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3D%20x%5E%7B1%2F3%7D)
Many calculators don't have a button labeled ![\sqrt[3]{}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%7D)
but they have the button 
to allow fractional exponents.
Answer and Explanation:
Since this is an isosceles right triangle, you can use the ratio of side lengths specific to this type of triangle where both legs are the hypotenuse over root 2:
u = v = 164√2 / √2 = 164
so:
u = 164
v = 164
Since center of dilation is the origin, this is easy. Just divide all of the x and y coordinate values by 3. Place the new point on the graph, and draw the triangle.
R' = R(3,6)/3 = (3/3,6/3)=(1,2). So R'(1,2)
S' = S(-3,6)/3 = (-3/3,6/3)=(-1,2). So S'(-1,2)
T' = T(-6,-6)/3 = (-6/3,-6/3)=(-2,-2). So T'(-2,-2)
So you now know the location of the 3 new points. R' at (1,2), S' at (-1,2) and T' at (-2,-2). Simply draw those 3 points on your graph and connect the lines to make a new triangle.
Answer:
(3, -3) is correct
Step-by-step explanation:
-4 × 3 = -12. -12 + 9 = -3
I think it’s 468 I might be wrong
