Answer:
m = 23.42 g
Explanation:
The question is incomplete, but I found this with these data:
<em>"A chemistry student needs 10.00 g of isopropenylbenzene for an experiment. He has available 120. g of a 42.7% w/w solution of isopropenylbenzene in carbon tetrachloride. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution'' button. Round your answer to 3 significant digits"</em>
If your data is different, you only need to replace the data here in the procedure and you should be fine.
Now, this actually is pretty easy to solve. You need 10 g, and you have 120 g of 42.7% solution of isopropenylbenzene in carbon tetrachloride.
Basically, the percent means the following:
For every 100 g of solution of tetrachloride, we have 42.7 g of isopropenylbenzene. And we just need 10 g, so, to know if we have enough solution we only have to do the following calculation:
%w/w = msto / msol * 100
From here, we just solve for mass of solution. If the solution is more than 120 g, then we click no solution, so let's see how much is the result:
42.7 = 10/msol * 100
msol = 10/42.7 * 100
<h2>
msol = 23.42 g</h2><h2>
We have enough solution.</h2>
✦ ✦ ✦ Beep Boop - Blu Bot! At Your Service! Scanning Question . . . Code :
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Answer:
The entropy of a substance can be obtained by measuring the heat required to raise the temperature a given amount, using a reversible process . The standard molar entropy, So, is the entropy of 1 mole of a substance in its standard state, at 1 atm of pressure. (Below are listed tips)
- At absolute zero (0 K), the entropy of a pure, perfect crystal is zero.
- The entropy of a substance can be obtained by measuring the heat required to raise the temperature a given amount, using a reversible process.
- The standard molar entropy, So, is the entropy of 1 mole of a substance in its standard state, at 1 atm of pressure.
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I think it would be d bc water is everywhere
The molarity of the HCl is 1 M when 12.0 of .500 M NaOH neutralized 6.0 ml of HCl solution.
Explanation:
Data given:
molarity of the base NaOH, Mbase =0. 5 M
volume of the base NaOH, Vbase = 12 ml
volume of the acid, Vacid = 6 ml
molarity of the acid, Macid = ?
The titration formula for acid and base is given as:
Mbase Vbase = Macid Vacid
Macid =
Macid = 1 M
we can see that 1 M solution of HCl was used to neutralize the basic solution of NaOH. The volume of NaOH is 12 ml and volume of HCl used is 6ml.
True! Acid-base reactions will always form water and a salt (not necessarily table salt, though!).
