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inna [77]
3 years ago
15

How many liters of a 0.30M solution are needed to give 2.7 moles of solute?

Chemistry
1 answer:
andreev551 [17]3 years ago
5 0
9, is 9 an option?? i hope this helps you
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Help Please
777dan777 [17]

Answer:

The force must be in the same direction as the object’s motion

Explanation:

Force is a physical quantity.

It is defined as the force applied to a body to move it in the direction of the force applied.

  Force  = mass x acceleration.

  • Force results in the acceleration of a body.
  • Force causes the change in position of a body and it moves it towards the direction of the applied force.
  • A force is a vector quantity having both magnitude and direction.

So, option is C is the correct choice.

8 0
3 years ago
Given the equation 2mg(s) + o2(g) → 2mgo(s) + 72.3 kj, how much heat is involved in the production of 5.0 mol of mgo? question 2
Rudik [331]
The heat is involved   in the  production of 5.0 mol of MgO  is   180 Kj

               calculation

2 Mg (s)   +O2 → 2 MgO

From  the  equation  above two  moles    of MgO  is used  therefore   

72.3   is for   2   moles

that is   72.3  kj =  2moles
                  ?      = 5  moles 

by  cross  multiplication

= 72.3  kj × 5/2     = 180  Kj  
    

7 0
3 years ago
Please help due today
KiRa [710]
Answer:

neodymium-145
7 0
3 years ago
The change in entropy of 20.0 moles of ideal monatomic constant volume gas as it changes from an initial temperature 300 K to it
Gre4nikov [31]

Answer:

668.9K is the final temperature

Explanation:

The change in entropy, ΔS, of an ideal monoatomic gas is obtained using the equation:

ΔS = n*Cv*ln (T2/T1)

<em>Where ΔS is change in entropy = 200J/K</em>

<em>n are moles = 20.0mol</em>

Cv is 3/2R for an ideal monoatomic gas (3/2*8.314J/molK)

T2 is final Temperature and T1 initial temperature = 300K

Replacing:

ΔS = n*Cv*ln (T2/T1)

200J/K = 20.0mol*3/2 *8.314J/molK*ln (T2/300K)

0.80186 = ln (T2/300K)

2.23 = T2 / 300K

<h3>668.9K is the final temperature</h3>
7 0
3 years ago
Convert 0.6330 mol of Na3PO4 to grams. Show the unit analysis by inserting the correct components into their unit- factor slots.
lys-0071 [83]

Answer:

No of moles = mass in gram / molar mass

Mass in gram = no of moles× molar mass

Mass in gram = 0.6330× 163.94

103.77 gram

Explanation:

5 0
3 years ago
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