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shusha [124]
3 years ago
7

Study the following reaction carefully. What classification should this reaction have?. . 2Al + 3NiBr2 2AlBr3 + 3Ni. . . synthes

is. decomposition. single replacement. double displacement. neutralization
Chemistry
2 answers:
quester [9]3 years ago
5 0
Balanced <span>chemical equation:

</span><span>2 Al + 3 NiBr</span>₂<span> = 2 AlBr</span>₃<span> + 3 Ni
</span>
Classification : <span>single replacement

hope this helps!</span>
Elenna [48]3 years ago
4 0

Answer;

Single replacement reaction

Explanation;

-There are five general types of reactions . These includes; combination, decomposition, single replacement, double replacement, combustion.

-Single replacement reactions are reactions in which both reactants and products consist of an element and a compound . For example in our case, for reactants, the element is Aluminium (Al) and the compound is NiBr2, and for products the element is Ni and the compound is AlBr3.

-Single replacement reactions involves a chemical change in which one element replaces a second element in a compound . In this case Aluminium (Al) replaces nickel (Ni) in the compound NiBr2.

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Pepsi [2]

Answer:

What's the equation?

3 0
3 years ago
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Answer:

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Explanation:

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6 0
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Please help<br><br> SOS<br><br> and explain please if you know how
vfiekz [6]

Answer:

<h2>1 N2+ 1 O2 are two N atoms and two O atoms.</h2>

<h3>In NO, there is one N and one O atom.</h3>

For both sides to be the same, there have to be 2 NO molecules, as 2 NO molecules contain 2 N atoms and 2 O atoms, just like starting products of the reaction.

8 0
3 years ago
The​ half-life of​ plutonium-241 is approximately 13 years. a. How much of a sample weighing 2 g will remain after 70 ​years? b.
Studentka2010 [4]

Answer: A) 0.0480 grams and B) 56.16 years.

Explanation: Half live is the time in which the amount of radioactive substance remains halve of its initial amount.

The formula we use for solving this type of problem is:

\frac{N}{N_0}=(\frac{1}{2})^n

where, N_0 is the initial amount and N is the remaining amount of radioactive substance and n is the number of half lives.

n=T/t_1_/_2

where, T is the time and t_1_/_2 is half life.

A) from given data, N_0 = 2 g

T = 70 years

t_1_/_2 = 13 years

N= ?

n=\frac{70years}{13years}

n = 5.38

\frac{N}{2g}=(\frac{1}{2})^5^.^3^8

\frac{N}{2g}=0.0240

N = 0.0480 g

So, 0.0480 grams of the substance will be remaining after 70 years.

B) N_0 = 2 g

N = 0.1 g

T = ?

Let's first calculate the value of n for this.

\frac{0.1}{2}=(\frac{1}{2})^n

0.05=0.5^n

Taking log to both sides:

log0.05=nlog0.5

-1.301=n(-0.3010)

n=\frac{1.3010}{0.3010}

n = 4.32

Half life is 13 years, so we can calculate the time as:

n=T/t_1_/_2

T=n*t_1_/_2

T=4.32*13years

T = 56.16 years

So, it will take 56.16 years for the radioactive substance to decay from 2 g to 0.1 g.

8 0
3 years ago
Read 2 more answers
If the reaction 2HgO --&gt; 2Hg + O2 is endothermic, which bonds are the strongest?
Alika [10]
  • Endothermic reaction means the reactant side takes heat from surrounding and get decomposed i.e ∆H=-ve
  • If the equation is exothermic then it means the reactant is happy to decompose .But it's not as it's endothermic

Now

  • HgO is Omitted from our solution option.

Hg is a atom so no bonds hence no bond strength occurs.

  • O_2 is a molecule and so it's our answer .
3 0
2 years ago
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