To multiply B and A, the number of columns of B must matc the number of rows of A.
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When we can multiply two matrices?</h3>
When we multiply two matrices, A and B, we multiply the rows of matrix A by the columns of matrix B.
Now, the number of elements in a row of a matrix, is equal to the number of columns (and the number of elements in a column is equal to the number of rows).
To multiply BxA:
Then, a row on matrix B must have the same number of elements than a column in row A.
Then, to multiply BxA, the number of columns of B must match the number of rows of A, meaning that the correct option is the last one.
If you want to learn more about matrices, you can read:
brainly.com/question/11989522
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.
2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.
3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.
4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.
Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
Answer:
f(x) = x^(1/2) + 3
Step-by-step explanation:
Translating to the right 3 units would change these:
0^(1/2) = 0 /// 3 units to the right would be (0,3)
1^(1/2) = 1 //// 3 units to the right would be (1,4)
4^(1/2) = 2 //// 3 units to the right would be (4,5) etc
Answer:
$0.25/g
Step-by-step explanation:
20g --- $5.00
1g --- 
× $5.00 = $0.25
Step 1: We make the assumption that 498 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$x.
Step 3: From step 1, it follows that $100\%=498$100%=498.
Step 4: In the same vein, $x\%=4$x%=4.
Step 5: This gives us a pair of simple equations:
$100\%=498(1)$100%=498(1).
$x\%=4(2)$x%=4(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{498}{4}$
100%
x%=
498
4
Step 7: Taking the inverse (or reciprocal) of both sides yields
$\frac{x\%}{100\%}=\frac{4}{498}$
x%
100%=
4
498
$\Rightarrow x=0.8\%$⇒x=0.8%
Therefore, $4$4 is $0.8\%$0.8% of $498$498.
