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jeka94
2 years ago
14

The measure of a central angle is 115°. The intercepted arc created by this central angle is a ___ arc.

Mathematics
1 answer:
Ad libitum [116K]2 years ago
5 0

Answer:

The intercepted arc is <u>115°</u> b/c the measure of a central angle is equal to the measure of its intercepted arc

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What is x for Unknown angle problems with algebra?
yulyashka [42]

The value of x=20

Step-by-step explanation:

We need to find the value of x

We are given a right angle which is equal to 90°

So, all three angles must sum to 90°

Our equation will be:

x+2x+(x+10)=90

Solving and finding value of x

x+2x+x+10=90\\4x=90-10\\4x=80\\x=80/4\\x=20

So, the value of x=20

Keywords: Angles

Learn more about angles at:

  • brainly.com/question/3202836
  • brainly.com/question/7151553

#learnwithBrainly

5 0
3 years ago
PLEASe PLEASE HeLP PLEASEEEEE
MA_775_DIABLO [31]

Answer:

option A

x=15/2

Step-by-step explanation:

refer to the above attachment

sorry for the messy writing:^

3 0
3 years ago
The medians of a triangle intersect at a point called the
lapo4ka [179]

Answer:

The medians of a triangle intersect at a point called the

centroid of the triangle

Step-by-step explanation:

The median of a triangle is a segment joining any vertex to the midpoint of the opposite side. The medians of a triangle are concurrent (they intersect in one common point). The point of concurrency of the medians is called the centroid of the triangle.

8 0
3 years ago
What is the simplest form of this expression?
Dimas [21]

Answer:

(4-m-1)-5

Remove the bracket

= 4-m-1-5

= -2-m

Hope this helps.

7 0
3 years ago
Let f(x)=x^3-x-1
alexira [117]
f(x) = x^3 - x - 1

To find the gradient of the tangent, we must first differentiate the function.

f'(x) = \frac{d}{dx}(x^3 - x - 1) = 3x^2 - 1

The gradient at x = 0 is given by evaluating f'(0).

f'(0) = 3(0)^2 - 1 = -1

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.

The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

y = -x + c

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

f(0) = (0)^3 - (0) - 1 = -1

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:

y = -x + c \\\\ -1 = -(0) + c \\\\ -1 = c \\\\ \text{Equation of tangent is } \boxed{y = -x - 1}
6 0
3 years ago
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