Not paying bills on time, or buying something you cant pay off.
Let's denote students in D = in the drama club , S<span> = in a sports team </span>
<span>P(D) = 85/330 </span>
<span>P(S) = 200/330 </span>
<span>
P(D and S) = 60/300 </span>
<span>
P(D or S) = P(D) + P(S) - P(D and S) </span><span>= 85/330 + 200/330 - 60/330 = 15/22 </span>
<span>
P(neither D nor S) = 1- 15/22 </span><span>= 7/22</span>
Answer:
The inter-decile range of IQ is 40.96.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

First decile:
100/10 = 10th percentile, which is X when Z has a pvalue of 0.1. So it is X when Z = -1.28.



Ninth decile:
9*(100/10) = 90th percentile, which is X when Z has a pvalue of 0.9. So it is X when Z = 1.28.



Interdecile range:
120.48 - 79.52 = 40.96
The inter-decile range of IQ is 40.96.
The answer is 405. i calculated or divided 36.45 by 0.09 and i got 405.
Answer:
6.02
Step-by-step explanation: