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AnnZ [28]
3 years ago
13

A 2-column table has 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is la

beled f (x) with entries one-eighth, one-fourth, one-half, 1, 2. What is the initial value of the exponential function represented by the table? One-eighth One-fourth One-half 1
Mathematics
2 answers:
andriy [413]3 years ago
10 0

Answer:

Initial value is \frac{1}{2}.

Step-by-step explanation:

Let us assume that the exponential function is f(x) = a(b)^{x} ...... (1)

Now, the point (0,\frac{1}{2}) will satisfy the above equation.

Now, this point on the graph of the exponential function will be sufficient to find the initial value of the function (1) i.e. a.

Now, putting the value x = 0 and y = \frac{1}{2} in the equation (1) we get, f(x) = a(b)^{x}

⇒ \frac{1}{2} = a(b)^{0} = a

⇒ a = \frac{1}{2} (Answer)

Vladimir [108]3 years ago
8 0

Answer:

1/2

Step-by-step explanation:

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