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Novosadov [1.4K]
3 years ago
11

Simplify into one fraction -2/x+3 - 4/x-5

Mathematics
2 answers:
alexira [117]3 years ago
7 0
You have to multiply each term by what it's missing for the denominators to both be the same.  The first term has x+3 but is missing x-5 so multiply top and bottom by x-5 and then distribute the numerator to -2x + 10.  Do the same for the other term that is missing the x+3 and distribute to get -(4x+12).  Distribute the negative in then simplify to get \frac{-6x-2}{(x+3)(x-5)} or simplify even further to get \frac{-2(3x+1)}{(x+3)(x-5)}
sergiy2304 [10]3 years ago
6 0
Multiply and divide by the product of the denominators.
\dfrac{-2}{x+3}+\dfrac{-4}{x-5}=\dfrac{-2(x-5)-4(x+3)}{(x+3)(x-5)}\\\\=\dfrac{-6x-2}{x^{2}-2x-15}
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