Use google that my advice
Answer:
about 26.6 times
Step-by-step explanation:
The circumference of the ball is found from ...
C = 2πr = 2π(4.3 in) ≈ 27.02 in
There are 12 inches per foot, so the 60 foot distance of interest is ...
(60 ft)×(12 in/ft) = 120 in
In terms of ball circumference, that distance is ...
(120 in)/(27.02 in/rotation) ≈ 26.6 rotations
If the ball starts rotating at the foul line, it will turn about 26.6 times before reaching the head pin.
(12x^3-4x^2+8x)/(-2x) The greatest common factor of the numerator and denominator is -2x so upon division by GCF of both numerator and denominator you have:
-6x^2+2x-4 and we can now also factor out -2
-2(3x^2-x+2)
Lets put ti this way:
P[1st serve good & wins point] = 60% * 70% = 42% = A
<span>P[2nd serve good & wins point] = 40% * 76% *57% = 17.328% = B </span>
<span>1. P[win point] = A+B = C = 59.328% <------- </span>
<span>2. P[1st serve good | win point ] = A/C = 42 / 59.328 = 0.707 or 70.7%
Please </span><span>remember that 2nd serve come into use only if 1st serve is not good</span>
Answer:
0.0195 = 1.95% probability that on any given day only John gets homework
Step-by-step explanation:
What is the probability that on any given day only John gets homework?
John has a 65% probability of getting homework.
Paul has a 100 - 80 = 20% probability of not getting homework.
Sonia has a 100 - 85 = 15% probability of not getting homework.
Since these events are independent, the probability is the multiplication.
0.65*0.2*0.15 = 0.0195
0.0195 = 1.95% probability that on any given day only John gets homework
