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Lyrx [107]
3 years ago
14

For each graph shown tell whether it shows a proportional relationship

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0

Answer:

a. yes, because there is a straight line that passes through the origin (0, 0). b. no, there is a straight line but it does not pass through the origin.

Step-by-step explanation:

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Find the area of a parallelogram with base b and height h b=74 cm h=14.8 cm
dexar [7]

The answer is A. 88.8 cm2

Work:

74 x 2 = 148

14.8 = 29.6

Add them = 177.6

then \frac{177.6}{2} = 88.8

5 0
4 years ago
Read 2 more answers
Kacey had 48 tickets for games at the school carnival. She used 1/3 of her tickets to play the spin-the-wheel game. She used hal
vovangra [49]

Answer:

32 tickets.

Step-by-step explanation:

First, 1/3 of 48 is 16. So 48-16= 32. Usually, people think the remaining half is half of 48, but it's supposed to be half of 32. So half of 32 is 16. So Kacey used 32 tickets for those 2 games.

6 0
4 years ago
Read 2 more answers
A regular
vivado [14]
The correct answer is The letter b
3 0
3 years ago
3RD TIME PLS REALLY NEED THIS
tatyana61 [14]

Answer:

Part A: a) Corresponding angles

Part B: b) 12x - 10 = 10x + 8

Part C: x = 9

m<1 = 98

m<2 = 82

Explanation:

B)

Since they're corresponding angles, they're equal to each other:

12x - 10 = 10x + 8

C)

12x - 10 = 10x + 8

2x = 18

x = 9

m<1:

12(9) - 10 = 98

m<2:

98 + y = 180

y = 82

6 0
3 years ago
Read 2 more answers
Please answer the two questions!
shutvik [7]

Given:

The expressions are

(c) \left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3

(d) \dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}

To find:

The simplified form of the given expression.

Solution:

(c)

We have,

\left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3

We know that, zero to the power of a non-zero number is always 1. So, \left(\dfrac{2^4\times 3^6}{12^2}\right)^0=1

\left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3=(1)^3

\left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3=1

Therefore, the value of the given expression is 1.

(d)

We have,

\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}

It can be written as

\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13^3\times 1}{(65\times 49)^2}

\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13\times 13\times 13}{(65\times 49)(65\times 49)}

\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13}{(5\times 49)(5\times 49)}

\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13}{60025}

\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13}{60025}

Therefore, the value of given expression is \dfrac{13}{60025}.

7 0
3 years ago
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