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2 years ago

For each graph shown tell whether it shows a proportional relationship

Mathematics

1 answer:

Soloha48 [4]2 years ago

6 0

Answer:

a. yes, because there is a straight line that passes through the origin (0, 0). b. no, there is a straight line but it does not pass through the origin.

Step-by-step explanation:

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Does anybody know the answer?

V125BC [204]

Answer:

option a

Explanation:

AD and DE are perpendicular lines, meaning they are at a 90° angle. likewise, AD and AB are also perpendicular lines. this means that there are 90° angles at ∠ADE and ∠DAB.

since both DE and AB are perpendicular to the same line and are positioned at the same angle away from it, they are parallel lines.

i hope this helps! :D

8 0

2 years ago

Plz help number 4 plz rn

ruslelena [56]

The answer for this qeustion is C.

7 0

3 years ago

Read 2 more answers

Please help I’m really need the help (NO LINKS ) (NO LYING )

MAVERICK [17]

Answer:

for this you should use photomath all you do is take a picture of each problem and put the answer down

7 0

3 years ago

Read 2 more answers

At a hockey game a vender sold a combined total of 105 sodas and hot dogs. The number of sodas sold was 39 more than the number

yKpoI14uk [10]

Answer:

Hot dog sold = 33

Sodas Sold = 72

Step-by-step explanation:

Given:

At a hockey game a vender sold a combined total of 105 sodas and hot dogs. The number of sodas sold was 39 more than the number of hot dogs sold

To Find:

Number of soda/hot dog sold

Solve:

h + ( 39 + h ) = 105

h + 39 + h = 105

2h + 39 = 105

h + 19.5 = 52.5

h = 52.5 - 19.5

This as a system does not use any inequality. "39 more than" means, +39.

h = 33 meaning d= 72

Add to check Answer:

33 + 72 = 105

Thus,

Hot dog sold = 33

Sodas Sold = 72

Kavinsky

3 0

1 year ago

A box designer has been charged with the task of determining the surface area of various open boxes (no lid) that can be constru

Viktor [21]

Answer:

1) $S = 2\cdot w\cdot l - 8\cdot x^{2}$ , 2) The domain of S is $0 \leq x \leq \frac{\sqrt{w\cdot l}}{2}$ . The range of S is $0 \leq S \leq 2\cdot w \cdot l$ , 3) $S = 176\,in^{2}$ , 4) $x \approx 4.528\,in$ , 5) $S = 164.830\,in^{2}$

Step-by-step explanation:

1) The function of the box is:

$S = 2\cdot (w - 2\cdot x)\cdot x + 2\cdot (l-2\cdot x)\cdot x +(w-2\cdot x)\cdot (l-2\cdot x)$

$S = 2\cdot w\cdot x - 4\cdot x^{2} + 2\cdot l\cdot x - 4\cdot x^{2} + w\cdot l -2\cdot (l + w)\cdot x + l\cdot w$

$S = 2\cdot (w+l)\cdot x - 8\cdpt x^{2} + 2\cdot w \cdot l - 2\cdot (l+w)\cdot x$

$S = 2\cdot w\cdot l - 8\cdot x^{2}$

2) The maximum cutout is:

$2\cdot w \cdot l - 8\cdot x^{2} = 0$

$w\cdot l - 4\cdot x^{2} = 0$

$4\cdot x^{2} = w\cdot l$

$x = \frac{\sqrt{w\cdot l}}{2}$

The domain of S is $0 \leq x \leq \frac{\sqrt{w\cdot l}}{2}$ . The range of S is $0 \leq S \leq 2\cdot w \cdot l$

3) The surface area when a 1'' x 1'' square is cut out is:

$S = 2\cdot (8\,in)\cdot (11.5\,in)-8\cdot (1\,in)^{2}$

$S = 176\,in^{2}$

4) The size is found by solving the following second-order polynomial:

$20\,in^{2} = 2 \cdot (8\,in)\cdot (11.5\,in)-8\cdot x^{2}$

$20\,in^{2} = 184\,in^{2} - 8\cdot x^{2}$

$8\cdot x^{2} - 164\,in^{2} = 0$

$x \approx 4.528\,in$

5) The equation of the box volume is:

$V = (w-2\cdot x)\cdot (l-2\cdot x) \cdot x$

$V = [w\cdot l -2\cdot (w+l)\cdot x + 4\cdot x^{2}]\cdot x$

$V = w\cdot l \cdot x - 2\cdot (w+l)\cdot x^{2} + 4\cdot x^{3}$

$V = (8\,in)\cdot (11.5\,in)\cdot x - 2\cdot (19.5\,in)\cdot x^{2} + 4\cdot x^{3}$

$V = (92\,in^{2})\cdot x - (39\,in)\cdot x^{2} + 4\cdot x^{3}$

The first derivative of the function is:

$V' = 92\,in^{2} - (78\,in)\cdot x + 12\cdot x^{2}$

The critical points are determined by equalizing the derivative to zero:

$12\cdot x^{2}-(78\,in)\cdot x + 92\,in^{2} = 0$

$x_{1} \approx 4.952\,in$

$x_{2}\approx 1.548\,in$

The second derivative is found afterwards:

$V'' = 24\cdot x - 78\,in$

After evaluating each critical point, it follows that $x_{1}$ is an absolute minimum and $x_{2}$ is an absolute maximum. Hence, the value of the cutoff so that volume is maximized is:

$x \approx 1.548\,in$

The surface area of the box is:

$S = 2\cdot (8\,in)\cdot (11.5\,in)-8\cdot (1.548\,in)^{2}$

$S = 164.830\,in^{2}$

4 0

2 years ago