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3 years ago

7

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1 answer:

Damm [24]3 years ago

6 0

Answer:

72

Step-by-step explanation:

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Kali had some candy to give to her five children. she first took seven pieces for herself and then evenly divided the rest among

elena55 [62]

If it is including herself then Kali would've started with 17 pieces of candy. But if it isn't herself then she would've started with 10 pieces of candy. Hope that helps.

8 0

3 years ago

the measure of an angle is fifty nine times the measure of its supplementary angle. What is the measure of each angle

Dimas [21]

9514 1404 393

Answer:

177°, 3°

Step-by-step explanation:

If the smaller angle is s, then the sum of the two angles is ...

s + 59s = 180°

s = 180°/60 = 3° . . . . . divide by the coefficient of s

59s = 177° . . . . . . . . . find the larger angle

The two angles are 177° and 3°.

7 0

3 years ago

Find the equation of ellipse passing throgh (1,4) and (-3,2)

irinina [24]

Answer:

$\displaystyle \frac{ {3x}^{2} }{ 35 } + \frac{{2y}^{2} }{ 35 } = 1$

Step-by-step explanation:

we want to figure out the ellipse equation which passes through <u>(</u><u>1</u><u>,</u><u>4</u><u>)</u><u> </u>and <u>(</u><u>-</u><u>3</u><u>,</u><u>2</u><u>)</u>

the standard form of ellipse equation is given by:

$\displaystyle \frac{(x - h {)}^{2} }{ {a}^{2} } + \frac{(y - k {)}^{2} }{ {b}^{2} } = 1$

where:

(h,k) is the centre
a is the horizontal redius
b is the vertical radius

since the centre of the equation is not mentioned, we'd assume it (0,0) therefore our equation will be:

$\displaystyle \frac{ {x}^{2} }{ {a}^{2} } + \frac{{y}^{2} }{ {b}^{2} } = 1$

substituting the value of x and y from the point (1,4),we'd acquire:

$\displaystyle \frac{ 1}{ {a}^{2} } + \frac{16}{ {b}^{2} } = 1$

similarly using the point (-3,2), we'd obtain:

$\displaystyle \frac{ 9}{ {a}^{2} } + \frac{4 }{ {b}^{2} } = 1$

let 1/a² and 1/b² be q and p respectively and transform the equation:

$\displaystyle \begin{cases} q + 16p = 1 \\ 9q + 4p = 1 \end{cases}$

solving the system of linear equation will yield:

$\displaystyle \begin{cases} q = \dfrac{3}{35} \\ \\ p = \dfrac{2}{35} \end{cases}$

substitute back:

$\displaystyle \begin{cases} \dfrac{1}{ {a}^{2} } = \dfrac{3}{35} \\ \\ \dfrac{1}{ {b}^{2} } = \dfrac{2}{35} \end{cases}$

divide both equation by 1 which yields:

$\displaystyle \begin{cases} {a}^{2} = \dfrac{35}{ 3} \\ \\ {b}^{2} = \dfrac{35}{2} \end{cases}$

substitute the value of a² and b² in the ellipse equation , thus:

$\displaystyle \frac{ {x}^{2} }{ \dfrac{35}{3} } + \frac{{y}^{2} }{ \dfrac{35}{2} } = 1$

simplify complex fraction:

$\displaystyle \frac{ {3x}^{2} }{ 35 } + \frac{{2y}^{2} }{ 35 } = 1$

and we're done!

(refer the attachment as well)

8 0

3 years ago

2x^2 + 3x - 12 when x = 5 help pls

cluponka [151]

$\huge\textsf{Hey there!}$

$\mathsf{2x^2 + 3x - 12}$

$\mathsf{= 2(5)^2 + 3(5) - 12}$

$\mathsf{5^2}$

$\mathsf{= 5 \times 5}$

$\mathsf{\bf = 25}$

$\mathsf{2(25) + 3(5) - 12}$

$\mathsf{2(25)}$

$\mathsf{= \bf 50}$

$\mathsf{3(5)}$

$\mathsf{= \bf 15}$

$\mathsf{= 50 + 15 - 12}$

$\mathsf{50 + 15}$

$\mathsf{= \bf 65}$

65 - 12

$\mathsf{= \bf 53}$

$\boxed{\boxed{\huge\textsf{Answer: \bf 53}}}\huge\checkmark$

$\large\textsf{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

5 0

3 years ago

Read 2 more answers

The sketch below shows part of the graph of y = ab*,

marysya [2.9K]

C because the line is kind of having a slope

4 0

3 years ago