<span>-1/11 + 5/11
= 5/11 - 1/11
= 4/11
Answer
</span><span>4/11</span>
Step-by-step explanation:
Draw diagonal AC
The triangle ABC has sides 17 and 25
Say AB is 17, BC is 25
Draw altitude on side BC from A , say h
h = 17 sin B
Area = 25*17 sin B = 408
sin B = 24/25
In ∆ ABC
Cos B = +- 7/25
= 625 + 289 — b^2 / 2*25*17
b^2 = 914 — 14*17 = 676
b = 26
h = 17*24/25 = 408/25 = 16.32
Draw the second diagonal BD
In ∆ BCD, draw altitude from D, say DE =h
BD^2 = h^2 + {(25 + sqrt (289 -h^2) }^2
BD^2 = 16.32^2 + (25 + 4.76)^2
= 885.6576 + 266.3424
BD = √ 1152 = 33.94 m
Velocity=distance/time
v=d/t
So in this case:
v=(3mi/5)/(3hr/8) that's the equation you need to solve.
v=(3m/5)*(8/3hr)
8/5 mph=(3m/5)*(8/3hr)
1 3/5 mph= (3/5)/(3/8)
So the first statement is correct.
((x+2)(x+2))-((x-5)(1))=A
x^2+4x+4-x+5=A
x^2+3x+9=A
Answer:
105 cm squared.
Step-by-step explanation:
(9)(6) + (6)(6) + (1/2)(5)(6) = 105.
