an=4n+1
Sum of first 30 terms
a1+a2+.................a30
Sn=(a1+an)*n/2
a1-----------first
terms
an=---------last
term-----a30
n= number of
terms-----30
calculation of a1
a1=4n+1=4*1+1=5
calculation of an
a30=4*30+1=121
S30=(a1+a30)*30/2
S30=(5+121)*30/2=1890
<span>The sum of first
30 terms is 1890</span>
Answer:
69.420π% c69 17o42
Step-by-step explanation:
hitler
Answer:
[/tex]y2=e^(-x)[/tex]
Step-by-step explanation:
CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLANATION


the graph of the parabola is above the x-axis, so the derivative is always positive and therefore the initial function is increasing in its whole domain.

The function is decreasing when its first derivative is negative. The first derivative of this function is negative for

so for

the function is decreasing.

The function is increasing when its first derivative is positive. The first derivative of this function is always negative therefore this function is never increasing.
Answer:
i believe thats correct
Step-by-step explanation: