Question

The length of a rectangle is 6 less than twice the width. If the perimeter is 60 inches, find the length and width.

Answer 1

Answer:

w = 12

l = 18

Step-by-step explanation:

Hello!

Recall the perimeter of a rectangle is twice the sum of the length and the width of the rectangle.

• $P = 2(l + w)$

Let w be the width. The length is 6 less than twice the width. That means, l is 2w - 6.

Plug it into the formula and solve, given that P is 60.

Solve for w

• $P = 2(l + w)$
• $60 = 2(2w - 6 + w)$
• $60 = 2(3w - 6)$
• $60 = 6w - 12$
• $72 = 6w$
• $w = 12$

The width is 12 inches. We can plug in 12 for 2w - 6 to find the length.

Solve for l

• $l = 2w - 6$
• $l = 2(12) - 6$
• $l = 24 - 6$
• $l = 18$

The length is 18 inches.

The width is 12 inches, and the length is 18 inches.