The length of a rectangle is 6 less than twice the width. If the perimeter is 60 inches, find the length and width.
1 answer:
Answer:
w = 12
l = 18
Step-by-step explanation:
Hello!
Recall the perimeter of a rectangle is <u>twice the sum of the length and the width of the rectangle.</u>
Let w be the width. The length is 6 less than twice the width. That means, l is 2w - 6.
Plug it into the formula and solve, given that P is 60.
<h3>Solve for w</h3>The width is 12 inches. We can plug in 12 for 2w - 6 to find the length.
<h3>Solve for l</h3>The length is 18 inches.
The width is 12 inches, and the length is 18 inches.
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Answer:
7. C. 6
8. H. √34
9. A. (1, 3.5)
10. J. 10
Step-by-step explanation:
7. AB = 2y, BC = 6y, AC = 48
AB + BC = AC (segment addition theorem)
Substitute the above values into the equation
2y + 6y = 48
Solve for y
8y = 48
Divide both sides by 8
8y/8 = 48/8
y = 6
8. Distance between P(2, 8) and Q(5, 3):
Let,
9. Midpoint (M) of segment LB, for L(8, 5) and B(-6, 2) is given as:
Let
Thus:
10. M = -10, N = -20
Distance between M and N, MN = |-20 - (-10)|
= |-20 + 10| = |-10|
MN = 10