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1 year ago

The length of a rectangle is 6 less than twice the width. If the perimeter is 60 inches, find the length and width.

Mathematics

1 answer:

pishuonlain [190]1 year ago

4 0

Answer:

w = 12

l = 18

Step-by-step explanation:

Hello!

Recall the perimeter of a rectangle is <u>twice the sum of the length and the width of the rectangle.</u>

$P = 2(l + w)$

Let w be the width. The length is 6 less than twice the width. That means, l is 2w - 6.

Plug it into the formula and solve, given that P is 60.

<h3>Solve for w</h3>

$P = 2(l + w)$
$60 = 2(2w - 6 + w)$
$60 = 2(3w - 6)$
$60 = 6w - 12$
$72 = 6w$
$w = 12$

The width is 12 inches. We can plug in 12 for 2w - 6 to find the length.

<h3>Solve for l</h3>

$l = 2w - 6$
$l = 2(12) - 6$
$l = 24 - 6$
$l = 18$

The length is 18 inches.

The width is 12 inches, and the length is 18 inches.

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