<u><em>≡ We know that:</em></u>
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<u><em>≡ Solution:</em></u>
⇒![\sqrt{[(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%5D%7D%20)
⇒![\sqrt{[(3-(-4))^{2}+(-1-(-5))^{2}]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%283-%28-4%29%29%5E%7B2%7D%2B%28-1-%28-5%29%29%5E%7B2%7D%5D%7D%20)
⇒![\sqrt{[7^{2}+4^{2}]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B7%5E%7B2%7D%2B4%5E%7B2%7D%5D%7D%20)
⇒![\sqrt{[49+16]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B49%2B16%5D%7D%20)
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<u><em>≡ Solution:</em></u>
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The length of a rectangle is 6 less than twice the width. If the perimeter is 60 inches, find the length and width.
1 answer:
Answer:
w = 12
l = 18
Step-by-step explanation:
Hello!
Recall the perimeter of a rectangle is <u>twice the sum of the length and the width of the rectangle.</u>
Let w be the width. The length is 6 less than twice the width. That means, l is 2w - 6.
Plug it into the formula and solve, given that P is 60.
<h3>Solve for w</h3>The width is 12 inches. We can plug in 12 for 2w - 6 to find the length.
<h3>Solve for l</h3>The length is 18 inches.
The width is 12 inches, and the length is 18 inches.
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