R = 804/91
8.835
this is ur answer i how i helped
Answer:200
Step-by-step explanation:is the answer
Hi there!
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I believe your answer is:
4
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Here’s why:
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- I am assuming that the fraction is supposed to be the exponent.
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![64^{\frac{1}{3}}\\--------\\\rightarrow \text{Recall the exponent rule: } a^{\frac{m}{n}}=(\sqrt[n]{a})^m\\\\\\\rightarrow \sqrt[3]{64}\\\\\rightarrow \boxed{4}](https://tex.z-dn.net/?f=64%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5C%5C--------%5C%5C%5Crightarrow%20%5Ctext%7BRecall%20the%20exponent%20rule%3A%20%7D%20a%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%28%5Csqrt%5Bn%5D%7Ba%7D%29%5Em%5C%5C%5C%5C%5C%5C%5Crightarrow%20%5Csqrt%5B3%5D%7B64%7D%5C%5C%5C%5C%5Crightarrow%20%20%5Cboxed%7B4%7D)
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Hope this helps you. I apologize if it’s incorrect.
Answer:
(3,2)
Step-by-step explanation:
the other three ordered pairs do not lie in the shaded region
<h3>
Answer: Independent</h3>
For two events A and B, if the occurrence of either event in no way affects the probability of the occurrence of the other event, then the two events are considered to be <u> independent </u> events.
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Explanation:
Consider the idea of flipping a coin and rolling a dice. If these actions are separate (i.e. they don't bump into each other), then one object won't affect the other. Hence, one probability won't change the other. We consider these events to be independent.
In contrast, let's say we're pulling out cards from a deck. If we don't put the first card back, then the future probabilities of other cards will change. This is considered dependent.
