Answer:
0,-11
just did it and got the answer correct
Answer: 0.3413
Step-by-step explanation:
Given: an American household generates an average of 28 pounds of newspaper for garbage or recycling. Assume the standard deviation is 2 pounds.
Let 
.
Let x be the random variable that denotes the amount of newspaper for garbage generated by each household each month.
If the data conforms to a normal distribution and a household is selected at random, the probability of its generating between 28 and 30 pounds per month is about
Hence, the required probability is 0.3413.
The we should use ANOVA instead of several t-tests to evaluate the differences in the mean of three or more groups.
<h3>What is t test?</h3>
A t- test is a measurable test that is utilized to look at the method for two gatherings. It is many times utilized in speculation testing to decide if a cycle or treatment really meaningfully affects the number of inhabitants in interest, or whether two gatherings are not quite the same as each other.
<h3>Explain ANOVA test:</h3>
The ANOVA test permits an examination of multiple gatherings simultaneously to decide if a relationship exists between them.
<h3 /><h3>According to question:</h3>
We ought to utilize ANOVA rather than a few t-tests to assess the distinctions in the mean of at least three gatherings on the grounds that without fail, we direct a t-test (between two gatherings) there is some opportunity that a Kind I blunder is being made while doing the test.
To know more about t-test visit:
brainly.com/question/15870238
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Answer:
9x -9
9(x - 1)
4(3x-3) - 3x + 3
( Hope this helps ) ＜（＾w＾）＞
