<span>-8 < x -3 < 1
we have two inequations:
* -8<x-3 and -8+3<x-3+3 or -5 < x or x>-5
* x-3<1 or x-3+3<1+3 and we have x<4
For all cases we have -5<x<4
or </span><span>interval notations: x</span>∈(-5;4)
have fun
Answer:
Step-by-step explanation:
There are two ways to do this. You could use your calculator to find out the decimal numbers that are equivalent to the two given fractions. Then check which one of the givens falls between these two numbers. I wouldn't do it that way -- not when you are told that the answer has 56 as the denominator. So ...
The best way to do it is to change the two givens so that they have a denominator of 56
3/7 = 3*8/7*8 = 24 / 56
7*7 / 7*8 = 49 / 46
So you need a number that is between 49 and 24
There is only one 27 / 56
Answer:
Any one of these three works:
plane MOU
plane MNU
plane NOU
Step-by-step explanation:
A plane can be named by a single letter, such as L in this problem, or by any three non-collinear points that lie on the plane. Non-collinear points are points that do not all lie in a single line.
Points M, N, O, and U lie on plane L, so you can choose any 3 of the 4 points to name the plane with, but make sure all 3 points are non-collinear.
To name plane L with points, you cannot use points MNO together since they are collinear, but you can name it using point U plus any two of the points M, N, and O.
plane L can be named
plane MOU
plane MNU
plane NOU
Do not name it plane MNO
RHS
=4x-27/0
=not defined=0
LHS
=x-2x+3x+4/7=2x+4/7=(14x+4)/7= 14x+4.
14x=-4
x=-4/14
X=-2/7
Answer with a Step-by-step explanation: We are given the table as:
x f(x)
0 6
2 7
4 0
7 5
i.e. corresponding to different values of x we are given the values of f(x)
we have to find the value of f(0)
i.e. we have to find the value of f(x) when x=0
As we can see from the table the value of f(x) at x=0 is 6
Hence, Correct option is:
C) 6
