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KiRa [710]
3 years ago
7

Write each of the following expression without using absolute value. |6m-54|, if m<9

Mathematics
1 answer:
Simora [160]3 years ago
3 0

9514 1404 393

Answer:

  54 -6m

Step-by-step explanation:

For values of m < 9, the argument of the absolute value function is less than 0. Then the expression evaluates to ...

  -(6m -54) = 54 -6m

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Find the midpoint given the endpoints (4,-10) (22,-4) Please do not use space when
Elza [17]

Answer: (13,-7)

Step-by-step explanation:

By using the formula (x_{m},y_{m})  =(\frac{x_{1}+x_{2}  }{2},\frac{y_{1}+y_{2}  }{2} )

(x_{m},y_{m})\\ is the coordinates of the midpoint.

For finding the midpoint X variable do:

(\frac{4+22}{2})=13

For finding the midpoint Y variable do:

\frac{-10+(-4)}{2} = -7 (you can either keep the parenthesis or take them out. Either way, the answer is the same.

Considering coordinate numbers follow the format: (x,y), you'll simply just substitute the numbers found above into their respective places.

x: 13

y: -7

(13,-7).

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3 years ago
a local hamburger shop sold a combined total of 628 hamburgers and cheeseburgers on Wednesday. There were 72 fewer cheeseburger
defon
There were 386 hamburger sold
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4 years ago
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of days an
solniwko [45]

Answer:

(a) 283 days

(b) 248 days

Step-by-step explanation:

The complete question is:

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. ​(a) What is the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths? ​(b) What is the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths?

Solution:

The random variable <em>X</em> can be defined as the pregnancy length in days.

Then, from the provided information X\sim N(\mu=268, \sigma^{2}=12^{2}).

(a)

The minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths implies that:

P (X > x) = 0.11

⇒ P (Z > z) = 0.11

⇒ <em>z</em> = 1.23

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\\\1.23=\frac{x-268}{12}\\\\x=268+(12\times 1.23)\\\\x=282.76\\\\x\approx 283

Thus, the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths is 283 days.

(b)

The maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths implies that:

P (X < x) = 0.05

⇒ P (Z < z) = 0.05

⇒ <em>z</em> = -1.645

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\\\-1.645=\frac{x-268}{12}\\\\x=268-(12\times 1.645)\\\\x=248.26\\\\x\approx 248

Thus, the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths is 248 days.

8 0
3 years ago
If the surface area of the rectangle below is 14x*2 -28, what is h?
Effectus [21]

Answer:

56

Step-by-step explanation:

because ur didviding 14 and too

6 0
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HELPPPPPPPP T^T I NEED AN ANSWER!!!! IS THE QUESATIN A OR C
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