Answer:
(4.5,-7)
Step-by-step explanation:
you add the x coordinates then divide them by 2
And then add the y coordinates then divide them by 2 also
1 yard = 3 feet
4 yards x 3 feet = 12 feet
12 feet is less than 13 feet
So False, 4 yards is <em>less than </em>13 feet
hope this helps
Answer:
Step-by-step explanation:
Hello!
a) The population of interest is the registered voters of the city of Raleigh.
b) This population is finite and its size is 10400 voters.
c) The sample was taken by making a telephone poll, calling 400 registered voters.
d) The sample size is n= 400 voters
The number of people that answered they'd vote for Brown are 151, so the sample proportion of voters that would vote for bron is:
p= 151/400= 0.3775 ≅ 0.38
e) To know how many people is expected to vote for Brown based on the results of the telephone poll you can do the following calculation:
10400*0.38= 3952
Based on the information obtained from the sample, it is expected that only 3952 voters will vote for Brown.
True by side angle side. You already have 2 congruent sides, so then do right angles congruence theorem to get the angles are congruent
Answer:
See the proof below.
Step-by-step explanation:
Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."
Solution to the problem
For this case we can assume that we have N independent variables 
with the following distribution:
bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:
From the info given we know that 
We need to proof that 
by the definition of binomial random variable then we need to show that:
The deduction is based on the definition of independent random variables, we can do this:
And for the variance of Z we can do this:
![Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2](https://tex.z-dn.net/?f=%20Var%28Z%29_%20%3D%20E%28N%29%20Var%28X%29%20%2B%20Var%20%28N%29%20%5BE%28X%29%5D%5E2%20)
![Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2](https://tex.z-dn.net/?f=%20Var%28Z%29%20%3DMpq%20%5Bp%281-p%29%5D%20%2B%20Mq%281-q%29%20p%5E2)
And if we take common factor 
we got:
![Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]](https://tex.z-dn.net/?f=%20Var%28Z%29%20%3DMpq%20%5B%281-p%29%20%2B%20%281-q%29p%5D%3D%20Mpq%5B1-p%20%2Bp-pq%5D%3D%20Mpq%5B1-pq%5D)
And as we can see then we can conclude that
