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Yuri [45]
3 years ago
5

(sint-cost)²=1-sin(2t)

Mathematics
1 answer:
Gemiola [76]3 years ago
4 0

i dont know the way you wan me to solve this but i got 1−2cos(t)sin(t)=1−2sin(t)cos(t)

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5. Find the sum of the first 35 terms of the arithmetic sequence when a = 5 and d = 4
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Answer:

The sum of the first 35 terms of the arithmetic sequence when a = 5 and d = 4 is 2555.

Step-by-step explanation:

Given:

a = 5

d =  4

To Find :

The sum of first 35 terms of the arithmetic sequence  = ?

Solution:

Step 1 : finding the 35th term

a_n = a_1 +(n-1)d

a_35 = 5 +(35-1)4

a_35 = 5 +(34)4

a_35 = 5 +136

a_35 = 141

Step 2: Finding the sum of first 35 terms

S_n = \frac{n(a_1 +a_n)}{2}

Substituting the values

S_n = \frac{35(5+141)}{2}

S_n = \frac{35(146)}{2}

S_n = \frac{35(146)}{2}

S_n = \frac{5110)}{2}

S_n = 2555

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Step-by-step explanation:

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Step-by-step explanation:

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