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GREYUIT [131]
3 years ago
14

Explain the process of solving inequality with variables on both sides. Show an example.

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

Inequalities work exactly like equations with one exception. The process begins just like equations: first, do the opposite of what you see, then do the same thing on the other side of the sign. At the last step of solving an inequality, if you multiply or divide by a negative number, then you reverse the sign

Masja [62]3 years ago
3 0
Give the answer above me brainliest they deserve it
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12.
kondaur [170]

Answer:

70kilometers

Step-by-step explanation:

first we must find how much one half of a centimeter is

well, its easy, theres already a half for the distance, and the representation is an even number, so cut it in half.

20-10 is 10

and now the multiplication

20x3=60

60+10=70

70 kilometers

3 0
3 years ago
Which statement is true about slope of the graphed line?
meriva

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A. the slope is negative

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
Help me answer this question please​
zaharov [31]

Answer:

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3 years ago
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A scientist claims that 7% 7 % of viruses are airborne. If the scientist is accurate, what is the probability that the proportio
Reptile [31]

Answer:

The probability is P(|p-\^{p}| >  0.03)  =   0.0040

Step-by-step explanation:

From the question we are told that

   The population proportion is p =  0.07

   The mean of the sampling distribution is   \mu_p =  0.07

   The sample size is n = 600

Generally the standard deviation is mathematically represented as

     \sigma_p  =  \sqrt{\frac{p (1 -p)}{n} }

=>    \sigma_p  =  \sqrt{\frac{0.07(1 -0.07)}{600} }    

=>    \sigma_p  =  0.010416    

Generally the probability that the proportion of airborne viruses in a sample of 600 viruses would differ from the population proportion by greater than 3% is mathematically represented as

      P(|p-\^{p}| >  0.03) =  1 - P(|p -\^{p}| \le 0.03)

=>   P(|p-\^{p}| >  0.03)  =  1 -  P(-0.03 \le p -\^{p} \le 0.03 )

Now  add p  to  both side of the inequality

=>   P(|p-\^{p}| >  0.03)  =  1 -  P( 0.07-0.03  \le \^{p} \le 0.03+ 0.07 )

=>   P(|p-\^{p}| >  0.03)  =  1 -  P(0.04 \le \^{p} \le 0.10 )

Now  converting the probabilities to their respective standardized score

=> P(|p-\^{p}| >  0.03)  =  1 -  P(\frac{0.04 - 0.07}{0.010416}  \le Z \le \frac{0.10 -0.07}{0.010416}  )

=> P(|p-\^{p}| >  0.03)  =  1 -  P(-2.88  \le Z \le 2.88 )

=>   P(|p-\^{p}| >  0.03)  =   1 - [P(Z \le 2.88) - P(Z \le -2.88)]

From the z-table  

       P(Z \le 2.88)  =  0.9980

and

       P(Z \le -2.88)  = 0.0020

So

     P(|p-\^{p}| >  0.03)  =   1 - [0.9980 - 0.0020]

=>   P(|p-\^{p}| >  0.03)  =   0.0040

     

7 0
3 years ago
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