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QveST [7]
3 years ago
5

The profitability, P, of a popular restaurant franchise can be modeled by the function P (t) = t4 – 10t3 + 28t2 – 24t, where t i

s the number of months since the restaurant opened. How many months after the franchise opens will it begin to show a profit?
A. 0 months
B. 2 months
C. 4 months
D. 6 months
Mathematics
1 answer:
vekshin13 years ago
8 0

In this question, the profit of the restaurant after t months is given by a polynomial function. To find when it begins to show a profit, we find the numerical values of the function for t, and it shows a profit when t > 0

Profit after t months:

P(t) = t^4 - 10t^3 + 28t^2 - 24t

0 months:

This is P(0). So

P(0) = 0^4 - 10*0^3 + 28*0^2 - 24*0 = 0

1 month:

This is P(1). So

P(1) = 1^4 - 10*1^3 + 28*1^2 - 24*1 = -5

2 months:

This is P(2). So

P(2) = 2^4 - 10*2^3 + 28*2^2 - 24*2 = 0

3 months:

This is P(3). So

P(3) = 3^4 - 10*3^3 + 28*3^2 - 24*3 = -9

4 months:

This is P(4). So

P(4) = 4^4 - 10*4^3 + 28*4^2 - 24*4 = -32

5 months:

This is P(5). So

P(5) = 5^4 - 10*5^3 + 28*5^2 - 24*5 = -45

6 months:

This is P(6). So

P(6) = 6^4 - 10*6^3 + 28*6^2 - 24*6 = 0

7 months:

This is `P(7). So

P(7) = 7^4 - 10*7^3 + 28*7^2 - 24*7 = 175

After 7 months it shows profit, so it starts showing profit on the 6th month, and thus, the correct answer is given by option D.

For another example of a function involving numeric value, you can check brainly.com/question/24231879

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Over [174]

\large{ \tt{❁ \: S \: O \: L \: U \: T \: I \: O \: N \: ❁}}

  • We're provided - Discount % = 10 % , Cost with VAT [ SP with VAT ] = Rs 4068 & VAT % = 13%. We're asked to find out the marked price of the bicycle. Let's start :

\large{ \tt{❇ \: FIND \: SP \: WITHOUT \: VAT \: / \: SP\: ❇}}

\large{ \tt{❃ \: SP  \: with \: VAT= SP + VAT\% \: of \: SP}}

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\large{ \tt{⇢ \: 4068 = SP +  \frac{13}{100}  \: sp}}

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\large{ \tt{⇢ \: 113 \: SP = 406800}}

\large{ \tt{⇢ \: SP =  \frac{406800}{113} }}

\large{ \tt{⇢ \: SP = 3600}}

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\large{ \tt{✽ \: NOW , \: FIND \: THE \: MP \:✽ }}

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\large{ \tt{⇾ \: 3600 = x -  \frac{10}{100} } \: x}

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\large{ \tt{⇾ \: 3600 =  \frac{90x}{100} }}

\large{ \tt{⇾ \: 90x = 360000}}

\large{ \tt{⇾ \: x =  \frac{360000}{90} }}

\large{ \tt{⇾ \: x = Rs \: 4000}}

\large{ \boxed{ \boxed{ \tt{☂ \: OUR \: FINAL \: ANSWER :  \boxed {\tt {\: Rs \: 4000}}}}}}

  • Hope I helped! Let me know if you have any questions regarding my answer and don't hesitate to reach out to me if you need any assistance! :)
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