a+b+c=0
[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]
[a^2+b^2+c^2+2ab+2ac+2bc=0]
[a^2+b^2+c^2=-(2ab+2ac+2bc)]
[a^2+b^2+c^2=-2(ab+ac+bc)] (i)
also
[a=-b-c]
[a^2=-ab-ac] (ii)
[-c=a+b]
[-bc=ab+b^2] (iii)
adding (ii) and (iii) ,we have
[a^2-bc=b^2-ac] (iv)
devide (i) by (iv)
[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
Answer:
30.00 – (1.79a + 0.36b + 2.99)
Step-by-step explanation:
you need to rest the amount of money pay.
<span>(x – 13)(x + 8) = 196
</span>x * x + x * 8 - 13 * x - 13 * 8 = 196
x² + 8x - 13x - 104 = 196
x² - 5x - 104 - 196 = 0
x² - 5x - 300 = 0
The missing side length is 28
Answer:
22x - 14
Step-by-step explanation:
pretty sure its like this..
3(4x-3)+5(2x-1)
= 3×4x + 3×(-3) + 5×2x + 5×(-1)
= 12x + (-9) + 10x + (-5)
and according to the rules of multiplying negative by positive...
= 12x - 9 + 10x - 5
combine like terms using the symbols on its left
= 12x + 10x - 9 - 5
= 22x - 14
V1 + V2
V1 = 1*2*1 = 2
V2 = 5*2*2 = 20
V1 + V2
2+20
22
