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Elodia [21]
3 years ago
14

Does anyone know the answer for the question below.

Mathematics
1 answer:
8090 [49]3 years ago
8 0

Answer: option C

Step-by-step explanation:

The diagram of the triangle is shown in the attached photo. The triangle is a right angle triangle ABC

Assuming the given angle is #,

Recalling the trigonometric ratio,

tan # = opposite / adjacent

If tan # = 4, it means

opposite / adjacent = 4/1

Therefore, opposite = 4 and adjacent = 1

Applying Pythagoras theorem,

Hypotenuse^2 = opposite ^2 + adjacent ^2

Hypotenuse = AC

Opposite = 4

Adjacent = 1

AC^2 = 4^2 + 1^2 = 17

AC = ± √17

To determine cos #, we would apply another trigonometric ratio,

Cos# = adjacent /hypotenuse

Cos# = 1/±√17

Cos # =-1 /√17 or 1/√17

You might be interested in
136/4g or 210/6g answer
Andrei [34K]

The answer is 1190 bec I simplified 136/4 or 210/6

Step-by-step explanation:

4 0
3 years ago
A quantity with an initial value of 4000 grows exponentially at a rate of 0.05% every 5 decades. What is the value of the quanti
icang [17]

The value of the quantity after 1 year, to the nearest hundredth is 4000.00

<h3>The exponential form of an equation</h3>

The standard exponential equation is eexpressed as:

P(t)=P_0e^{kt}

Given the following parameters

P_0=4000\\r =0.0005\\t = \frac{1}{50} =0.02 (yearly)

Substitute into the formula to have:

P(t)=4000e^{0.0005(0.02)}\\P(1)=4000e^{0.00001}\\P(1)=4000

Hence the value of the quantity after 1 year, to the nearest hundredth is 4000.00

Learn more on exponential equations here: brainly.com/question/12940982

6 0
3 years ago
|2-5x|+3&lt;10 how to solve
ivann1987 [24]
1 Simplify — 2 <span>Equation at the end of step  1  :</span> 2 3 1 ((— • x) - ——) - — = 0 5 10 2 <span> Step  2  :</span> 3 Simplify —— 10 <span>Equation at the end of step  2  :</span> 2 3 1 ((— • x) - ——) - — = 0 5 10 2 <span> Step  3  :</span> 2 Simplify — 5 <span>Equation at the end of step  3  :</span> 2 3 1 ((— • x) - ——) - — = 0 5 10 2 <span> Step  4  :</span>Calculating the Least Common Multiple :

<span> 4.1 </span>   Find the Least Common Multiple

      The left denominator is :      <span> 5 </span>

      The right denominator is :      <span> 10 </span>

<span><span>        Number of times each prime factor
        appears in the factorization of:</span><span><span><span> Prime 
 Factor </span><span> Left 
 Denominator </span><span> Right 
 Denominator </span><span> L.C.M = Max 
 {Left,Right} </span></span><span>5111</span><span>2011</span><span><span> Product of all 
 Prime Factors </span>51010</span></span></span>


      Least Common Multiple:
      10 

Calculating Multipliers :

<span> 4.2 </span>   Calculate multipliers for the two fractions


    Denote the Least Common Multiple by  L.C.M 
    Denote the Left Multiplier by  Left_M 
    Denote the Right Multiplier by  Right_M 
    Denote the Left Deniminator by  L_Deno 
    Denote the Right Multiplier by  R_Deno 

   Left_M = L.C.M / L_Deno = 2

   Right_M = L.C.M / R_Deno = 1

Making Equivalent Fractions :

<span> 4.3 </span>     Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent, <span> y/(y+1)2  </span> and <span> (y2+y)/(y+1)3  </span>are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

<span> L. Mult. • L. Num. 2x • 2 —————————————————— = —————— L.C.M 10 R. Mult. • R. Num. 3 —————————————————— = —— L.C.M 10 </span>Adding fractions that have a common denominator :

<span> 4.4 </span>      Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2x • 2 - (3) 4x - 3 ———————————— = —————— 10 10 <span>Equation at the end of step  4  :</span> (4x - 3) 1 ———————— - — = 0 10 2 <span> Step  5  :</span>Calculating the Least Common Multiple :

<span> 5.1 </span>   Find the Least Common Multiple

      The left denominator is :      <span> 10 </span>

      The right denominator is :      <span> 2 </span>

<span><span>        Number of times each prime factor
        appears in the factorization of:</span><span><span><span> Prime 
 Factor </span><span> Left 
 Denominator </span><span> Right 
 Denominator </span><span> L.C.M = Max 
 {Left,Right} </span></span><span>2111</span><span>5101</span><span><span> Product of all 
 Prime Factors </span>10210</span></span></span>


      Least Common Multiple:
      10 

Calculating Multipliers :

<span> 5.2 </span>   Calculate multipliers for the two fractions


    Denote the Least Common Multiple by  L.C.M 
    Denote the Left Multiplier by  Left_M 
    Denote the Right Multiplier by  Right_M 
    Denote the Left Deniminator by  L_Deno 
    Denote the Right Multiplier by  R_Deno 

   Left_M = L.C.M / L_Deno = 1

   Right_M = L.C.M / R_Deno = 5

Making Equivalent Fractions :

<span> 5.3 </span>     Rewrite the two fractions into equivalent fractions

<span> L. Mult. • L. Num. (4x-3) —————————————————— = —————— L.C.M 10 R. Mult. • R. Num. 5 —————————————————— = —— L.C.M 10 </span>Adding fractions that have a common denominator :

<span> 5.4 </span>      Adding up the two equivalent fractions

(4x-3) - (5) 4x - 8 ———————————— = —————— 10 10 <span> Step  6  :</span>Pulling out like terms :

<span> 6.1 </span>    Pull out like factors :

   4x - 8  =   4 • (x - 2) 

<span>Equation at the end of step  6  :</span> 4 • (x - 2) ——————————— = 0 10 <span> Step  7  :</span>When a fraction equals zero :<span><span> 7.1 </span>   When a fraction equals zero ...</span>

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

4•(x-2) ——————— • 10 = 0 • 10 10

Now, on the left hand side, the <span> 10 </span> cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
   4  •  (x-2)  = 0

Equations which are never true :

<span> 7.2 </span>     Solve :    4   =  0

<span>This equation has no solution.
</span> A a non-zero constant never equals zero.

Solving a Single Variable Equation :

<span> 7.3 </span>     Solve  :    x-2 = 0<span> 

 </span>Add  2  to both sides of the equation :<span> 
 </span>                     x = 2

One solution was found :                   x = 2

<span>
</span>

4 0
3 years ago
Would you rather 36 spherical bottles with radi = 4.57 or three 12-packs of cans if each box is 15inx5inx4.4in
grigory [225]

Answer:

  36 bottles

Step-by-step explanation:

Each spherical bottle will have a volume of ...

  V = (4/3)πr³ = (4/3)π(4.57³) = 399.8 . . . . cubic inches

Each box (12-pack?) will have a volume of ...

  V = LWH = (15 in)(5 in)(4.4 in) = 330 in³

This is a smaller volume than even one spherical bottle, so 36 bottles will have the larger volume.

5 0
4 years ago
The manufacturer of a certain type of new cell phone battery claims that the average life span of the batteries is 500 charges;
maxonik [38]

Answer:

a. 0

b. Yes

c. The manufacturers claim is not plausible

d. 0.3446

e. A sample mean life time of 39.8hr is not unusually short.

f. The manufacturers claim us plausible

Step-by-step explanation:

Please see attachment

8 0
4 years ago
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