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3 years ago

:) please answer question quick will give brainliest already did one answer

Mathematics

1 answer:

vodomira [7]3 years ago

6 0

66,000 because the probe travels 12,000 miles per hour. So 12,000 times 5.5 is 66,000. Hope this helps.

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Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 47.3 m

Harlamova29_29 [7]

Answer:

47.4167

D. The computed mean is close to the actual mean because the difference between the means is less than 5%

Step-by-step explanation:

Given the distribution :

Speed(m/hr) ___ midpoint(x) ___ F ___fx

42 - 45 _______ 43.5 ________21 __ 913.5

46 - 49 _______47.5 _________15 __712.5

50 - 53 _______ 51.5 _________6 __ 309

54 - 57 _______ 55.5 ________ 4 ___ 222

58 - 61 ________59.5 ________ 2 ___ 119

The midpoint, x= sum of lower and upper boundary divided by 2

For instance, (42 + 45) / 2 = 43.5

The computed mean, Σfx / Σf = 2276 / 48 = 47.4167

Actual mean = 47.3 miles

(47.4167 - 47.3) / 47.3 * 100% = 0.24%

6 0

3 years ago

g A slot machine has three slots; each will show a cherry, a lemon, a star, or a bar when spun. The player wins if all three slo

Law Incorporation [45]

Answer:

Step-by-step explanation:

Let us consider E_abc to be the event that a, b and c appear on the first, second and third slot of the spin machine.

Now, we are told that each slot has 4 possibilities which are a cherry, a lemon, a star, or a bar when spun.

Thus, from mn rule in probability, the total number of simple events in the sample space is = 4³ = 64

7 0

3 years ago

HELP ASAP!!!!! Given: Point B is on the perpendicular bisector of AC¯¯¯¯¯. BD¯¯¯¯¯ bisects AC¯¯¯¯¯ at point D. Prove: B is equid

Harlamova29_29 [7]

Answer: Missing parts are,

In first blank, $AD\cong DC$ ,

In second blank, SAS postulate

In third blank, CPCTC postulate

Step-by-step explanation:

Since, Here D is the mid point on the line segment AC.

And BD is a perpendicular to the line AC.

Therefore, In triangles ADB and CDB ( shown in figure)

AD\cong DC ( By the definition of mid point)

$\angle BDA\cong \angle BDC$ ( right angles )

$BD\cong BD$ ( reflexive)

Thus, By SAS ( side angle side )postulate,

$\triangle ADB\cong \triangle CDB$

So, by CPCTC( Corresponding parts of congruent triangles are congruent)

$AB\cong CB$

Now, By definition of congruent segment,

AB=CB

By definition of equidistant,

B is equally far from both A and C.

7 0

3 years ago

Read 2 more answers

Does anyone know how to do this question ??

Viktor [21]

Y^2-9^2

(y-9)(y+9)

To see if its right:

y*y+y*9-9*y-9*9
y^2+9y-9y-81
y^2-9^2

4 0

3 years ago

A side of the triangle below has been extended to form an exterior angle of 164º. Find the value of x.

OverLord2011 [107]

Answer:

x=111

Step-by-step explanation:

the supplementary angle is 16. triangles should add up to 180.

4 0

3 years ago