EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEFEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
Answer:
128
Step-by-step explanation:
16 + 16 = 32
32 + 32 = 64
64 + 64 = 128
Hope this helps!!
Problem Example :
Given: HF || JK; HG ≅ JG
Prove: FHG ≅ KJG
Answer: A. ∠FGH ≅∠KGJ because vertical angles are congruent.
Answer: wanna sprite cranberry?
Step-by-step explanation:
Answer:The measure of the arc RPQ is 205°
Step-by-step explanation:
Given the figure in which
m∠ROP=125°
we have to find the measure of the arc RPQ.
As QP is diameter i.e a straight line therefore
∠1 and ∠2 forms a linear pair hence these angles are supplementary.
By supplementary law
∠1+∠2=180°
∠1+125°=180°
∠1=180°-125°=55°
Now we have to find the measure of the arc RPQ i.e
we have to find the measure of ∠2+∠3
By theorem, angles around a point will always add up to 360 degrees.
∴ ∠1+∠2+∠3=360°
55°+∠2+∠3=360°
∠2+∠3=860-55=205°
Hence, the measure of the arc RPQ is 205°
