A quadrilateral with two pairs of consecutive sides congruent and no opposite sides congruent is called a(n)

I NEED HELP!!!!

Ratling [72]

Answer:

8. False.

11 and 13 are consecutive prime numbers, but 11 + 13 = 24 and 24 isn't prime.

9. True.

10. True.

11. True

12. False.

$|-3+1|= 2\\|-3|+|1|=4$

13. True.

7 0

3 years ago

what is the quotient of 0.457 and 0.12? round to the hundredths place show your work Will.mark brainiest

ExtremeBDS [4]

I stopped the division process once I got to the thousandths place. 0.457 ÷ 0.12 ≈ 3.808. Rounded to the hundredths place, the answer is 3.81.

3 0

3 years ago

Which system of equations will yield the same solution as x-y=3 2x-3y=-1

laiz [17]

Answer: Is there some answer choices? Because I can't help if I don't have any choices.

Step-by-step explanation:

5 0

3 years ago

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.372 minute. The winning ca

Fed [463]

Answer:

Sam had a finish time with a z-score of -2.93.

Karen had a finish time with a z-score -1.91.

Sam had the more convincing victory.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Sam:

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.372 minute. The winning car, driven by Sam, finished in 185.85 minutes.

So $\mu = 186.94, \mu = 0.372, X = 185.85$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{185.85 - 186.94}{0.372}$

$Z = -2.93$

Sam finishing time was 2.93 standard deviations below the mean.

Sam had a finish time with a z-score of -2.93.

Karen:

The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

So $\mu = 110.7, \sigma = 0.115, X = 110.48$