Answer:
Using a bar graph where one bar has a length of 2.4 and one bar has a length of 1.8
Step-by-step explanation:
You use a bar graph to compare things between different groups, so it is the most appropriate one to use.
You use a pie chart to compare parts of a whole, so it would not be appropriate.
The graph should represent the relative sizes of the two values (24:18 or 1.33:1). Using a square or a cube would distort the relationship. The relative area of the squares would be 1.77:1 and that of the cubes would be 2.37:1.
Answer:
option C and F
Step-by-step explanation:
Given excluded value is x=-5
Excluded value are the values that makes the denominator 0
Now we check out each option and see , in which option the denominator becomes 0 when x=-5
When denominator has (x+5) then when we plug in x=-5
(x+5) becomes (-5+5) =0
So we look at the options that has factor (x+5) in the denominator
In option C we have x^2 -25
When we plug in -5 for x then it becomes (-5)^2 - 25 =0
So x=-5 makes the denominator 0
-5 is an excluded value for option C
Last option f has x+5 in the denominator
x=-5 make the denominator 0
so , -5 is an excluded value for option F
The first one is the answer because
|6-5|<3 and 1<3
|4-5|<3 and -1<3
|2-5|<3 and -3<3
|0-5|<3 and -5<3
|-2-5|<3 and -7<3
|-4-5|<3 and -9<3
|-6-5|<3 and -11<3
Let the required weight be X, then
z = (X - mean)/standard deviation
2 = (X - 16)/1
X - 16 = 2
X = 2 + 16
X = 18 oz.
Answer:
6(2) -2(-5) Substitute the values given into the expression and multiply. 12+10 ... 1. 2x-(3-4y), when x = 5 and y=-3. 215)-(3-4(-3)). 10-(3+12). 10-15. 2. ... + (3 - 3 x + 1 +. 6-3x = 4x + 4. Bebetto. 2=7x -. - 4-2=34+12. - ý 2=2y+12. + ... y = 2x-1. Simplify. Subtract 2x from each side. Multiply both sides by -1. 2+3 m.
Step-by-step explanation:
If 2x + y = 7 and x + 2y = 5, then (x + y)/3 = (A) 1 (B) 4/3 (C) 17/5 (D) ... Divide both sides by 3 to get: x + y = 4 ... 2*(x+2y = 5) equals 2x+4y=10 ... or subtracting one from the other and it likely happens 90% times that ... If a question involves a system of two equations, and we're asked to find the value of ONE
