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kow [346]
3 years ago
5

A metric ruler can be used to measure what type of object?? Please help me!!

Mathematics
2 answers:
Xelga [282]3 years ago
8 0

Answer:

A pencil

Step-by-step explanation:

Reil [10]3 years ago
3 0

Answer: a water bottle

Step-by-step explanation:

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Determined be whether the solution to 32=6(1)-4​
igomit [66]

Answer:

false

Step-by-step explanation:

32 = 6(1) - 4

According to PEMDAS (parentheses/exponents | multiplication/division | additions/subtraction), we should multiply first.

32 = 6 - 4

Now let's subtract.

32 = 2

This statement is incorrect; therefore it is not true.

8 0
3 years ago
Read 2 more answers
What’s the mean of the numbers 63,73,92,63,93
Igoryamba

Answer:

76.8

Step-by-step explanation:

The mean is the sum of the values divided by the total number of values.

63+73+92+63+93 / 5 =

384 / 5 = 76.8

7 0
3 years ago
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What problem cannot be solved using the law of sines?
Radda [10]
<span>When to use the law of sines formula. You should use the law of sines when you know 2 sides and an angle and you want to find the measure of an angle opposite a known side. Or when you know 2 angles and 1 side and want to get the side opposite a known angle.</span>
3 0
3 years ago
I need help with reflections on a graph, I'll mark brainliest. Please help me.
kvv77 [185]

Answer: 1) (0,-3) 2) (4,-2) 3) (2,3) 4) (-2,2)

Step-by-step explanation: Hope this helps!

3 0
3 years ago
Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p
scZoUnD [109]

Answer:

The probability that they will teach different courses is \frac{2}{3}.

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Compute the probability that they will teach different courses as follows:

P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}

Thus, the probability that they will teach different courses is \frac{2}{3}.

3 0
3 years ago
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