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3 years ago

A robot can complete 8 tasks in 5/6 hour. Each task takes the same amount of time.

Mathematics

1 answer:

lesantik [10]3 years ago

5 0

Answer:

28‏/10‏/2017 — 5/6 hour = 5/6 × 60 = 300/6 = 50 minutes8 tasks in 50 minutes1 task = 50/8 = 6 ... takes the same amount of time. a. how long does it take the robot to complete the task? b. how many tasks can the robot complete in one hour?

Step-by-step explanation:

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Gemiola [76]

Answer:

Use both methods to calculate the sale price of an item that costs $140 and has a discount of. 40%. 140 x.40 = 56. 140-56 +84. 140x.60 = $84.

Step-by-step explanation:

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3 years ago

Y=-4x-2 and intersects at the points (4,-1)

rosijanka [135]

Answer:

It doesn't intersect at that point

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3 years ago

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Alden paid to have some programs printed for the football game last weekend. The printing cost per program was 54 cents, and the

uranmaximum [27]

Answer:

300 programs

Step-by-step explanation:

Let’s work with cents to make this easier. We convert the $12 to cents, making 1200 cents

Let the number of copies Alden printed be x. His total printing cost would be x * 54 = 54x cents.

He sold at 75 cents each and still had left 100 copies. This means his total sale would be (x - 100)75

He lost $12 on the venture. This means his cost price minus his selling price is $12 since it’s a loss.

Computing this:

54x - 75(x - 100) = 1200

54x - 75x + 7500 = 1200

-21x = 1200 - 7500

-21x = -6,300

x = 6300/21 = 300 programs

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3 years ago

Find the product.<br> (2x – 2y^2) (4x + y^2)

Serggg [28]

56xy^2 -56y^4 Hope it helps!

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3 years ago

A cell of some bacteria divides into two cells every 10 minutes.The initial population is 3 bacteria. (a) Find the size of the p

mars1129 [50]

Answer:

(a) $P_{t}=3(2)^{6t}$

(b) $3(2)^{42}$

Step-by-step explanation:

A cell of some bacteria divides itself into 2 cells in every 10 minutes and initial population of the bacteria was 3.

That means sequence formed will be 3, 6, 12, 24............

We can easily say that this sequence is a geometric sequence having common ratio (r) = $\frac{T_{2}}{T_{1}}=\frac{6}{3}$

r = 2

Now we know the explicit formula of a geometric sequence is given by

$P_{t}=P_{0}(r)^{\frac{60t}{10}}=P_{0}(r)^{6t}$

Where a = Initial population = 3 bacteria

r = common ratio = 2

and t = time in hours

So explicit formula will be $P_{t}=3(2)^{6t}$

(a) Now we have to calculate the size of population after t hours

$P_{t}=3(2)^{6t}$

(b) We have to find the size of population after 7 hours or 420 minutes

$P_{t}=3(2)^{6\times7}$

= $3(2)^{42}$

After 7 hours bacteria population will be $3(2)^{42}$

By the explicit formula

$21=3(2)^{6t}$

$2^{6t}=\frac{21}{3}=7$

Now we take log on both the sides of the equation

$log(2^{6t})=log(7)$

6t log2 = log 7

6t(0.301) = 0.845

t(1.806) = 0.845

t = $\frac{0.845}{1.806}=0.468$ hours

Or t = 0.468×60 = 28.07 minutes

Therefore, after 28.07 minutes bacterial population will be 21

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3 years ago