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yan [13]
3 years ago
5

3x+(2−4x) what is the answer of this pre algebra question

Mathematics
2 answers:
Brums [2.3K]3 years ago
8 0

Answer:

-x+2

Step-by-step explanation:

3x+(2−4x)

=3x+2-4x

=3x-4x+2

=-x+2

I hope this helps!

Dahasolnce [82]3 years ago
8 0

Answer:

Let's simplify step-by-step.

3x+2−4x

=3x+2+−4x

Combine Like Terms:

=3x+2+−4x

=(3x+−4x)+(2)

=−x+2

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What is the solution to the equation 3/4y+1/4=1+y , given the replacement set {−4, −3, −2} ?
ivann1987 [24]

Answer:

It's -3 mate

Step-by-step explanation:

I just did the test

8 0
3 years ago
Similfy 1/2 (30x + 4y - 14 ) +1/4 (16x - 28y + 4)
Hoochie [10]

Answer:

19x - 5y - 6

Hope this helped

Step-by-step explanation:

You start by simplifying each expression, you will be distributing the number outside the parentheses  on each number inside the parentheses

1/2(30x+4y-14)

1/4(16x -28 +4)

leaving you with

15x + 2y - 7 + 4x - 7y + 1

combine the x's y's and the singular numbers

19x - 5y - 6

Brainliest?


6 0
3 years ago
The parent function f(x) = 1.5x is translated such that the function g(x) = 1.5x + 1 + 2 represents the new function. Which is t
Gennadij [26K]

graph of g is the the graph of f shifted 3 units above

i dont know if the translator translate that coreclty

6 0
3 years ago
Read 2 more answers
For waht values of x do the vectors -1,0,-1), (2,1,2), (1,1, x) form a basis for R3?
DaniilM [7]
<h2>Answer:</h2>

The values of x for which the given vectors are basis for R³ is:

                        x\neq 1

<h2>Step-by-step explanation:</h2>

We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.

We are given three vectors as:

(-1,0,-1), (2,1,2), (1,1, x)

The matrix formed by these vectors is:

\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]

Now, the determinant of this matrix is:

\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-1(x-2)-2(1)+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+2-2+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+1

Hence,

-x+1\neq 0\\\\\\i.e.\\\\\\x\neq 1

4 0
3 years ago
How do you translate "the sum of 5 and the product of a number times 3"?
Lubov Fominskaja [6]

Answer:

5+ 3x

Step-by-step explanation:

3 0
4 years ago
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