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To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band
[recall 
or 20(x+5) if you wish.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band
Answer:
if
Step-by-step explanation:
Recall some following basic ideas about absolute value:
or I guess
or just
but there is a reason why I wrote it the way I did.
You see that the absolute value returned the same value if the value was positive.
You see that the absolute value returned the opposite value if the value was negative.
You can include 0 in either.
Let's look at alone for a second.
* if
is positive or zero.
When is positive or zero? [greater than or equal to 0]
Subtract 3 on both sides
* if
is negative or zero.
When is negative or zero? [less or equal to 0]
Subtract 3 on both sides
So looking at the bullet points (the *), fits into the first inequality.
Therefore, .