I got y=2/5x+31/5 as the answer
K/5 + 3 - 3k = -6k
Steps
Subtract 3 from both sides
k/5 + 3 - 3k - 3 = -6k - 3
Then simplify,
k/5 - 3k = -6k - 3
Add 6k to both sides
k/5 - 3k + 6k = -6k - 3 + 6k
Simplify,
k/5 + 3k = -3
Next, multiply both sides by 5
k/5 * 5 + 3k * 5 = -3 * 5
So,
k + 15k = -15
16k = -15
Then, divide both sides by 16
16k/16 = -15/16
Simplify,
k = -15/16
The formula to find the discriminant equals D = b^2-4ac.
(Quadratic equations have the formula ax^2+bx+c. A = -1, B = +4, C = -2.)
D = 4^2-4(-1)(-2). 8-8 = 0.
0 = 1 solution
-D = 0 solutions
+D = 2 solutions
The discriminant equals 0, also establishing that if you were asked to find the solutions, there would only be one.
Step-by-step explanation:
Do you need answers to all of them of some of them?
1. (4.5×10¹²)÷(9×10^10)
(45×10^-1×10¹²)÷(9×10^10)
(45×10¹¹)÷(9×10^10)
(45÷9)×(10¹¹÷10^10)
5×10
if you need help with the others kindly let me know
