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KATRIN_1 [288]
2 years ago
15

Can somebody help me? Thank you!

Mathematics
1 answer:
damaskus [11]2 years ago
6 0

Answer:

Option a

Step-by-step explanation:

SSS=SSS

This is the answer pls mark brainliest

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Cole builds a rocket with the dimensions shown. Suppose the rocket separates into the original parts before falling to Earth. Ho
agasfer [191]

Answer:

In flight, a rocket is subjected to the forces of weight, thrust, and aerodynamics. On this slide, we have removed the outer "skin" so that we can see the parts. The payload of the German V2, shown in the figure, was several thousand

Step-by-step explanation:

3 0
2 years ago
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Please help me with this i need help she is gonna call my mom again!!!​
telo118 [61]

Answer:

1. 15

2. -23

3. -16

Step-by-step explanation:

1. Find h(-8)

h(t) = \frac{5}{4}(4 - t)

h(-8) = \frac{5}{4}(4 -(-8))

h(-8) = \frac{5}{4}(4+8) =\frac{5}{4}(12)=5(3)=15

2. What is the value of g(-3)

g(x) = 4(x - 5) + x^{2}

g(-3) = 4(-3 - 5) -3^{2}

g(-3) = 4(-8) + 9

g(-3) = -32 + 9

g(-3) = -23

3. Find f(10)

f(x) = 14 - 3x

f(10) = 14 - 3(10)

f(10) = 14 - 30

f(10) = -16

7 0
3 years ago
Read 2 more answers
-5x+ 10 = =5y<br> Slope-Intercept Form
I am Lyosha [343]

\Huge\boxed{\boxed{y=-x+2}}

\large\textsf{Explanation:}

-5x+10=5y

Use the symmetric property to flip the sides of the equation.

5y=-5x+10

Divide everything by 5.

\Large\boxed{y=-x+2}

8 0
3 years ago
A model car has a scale factor of 1 64 164 The diameter of a tire on the model is 0.41 inches. So, the diameter of the tire on a
Alchen [17]

Answer: 26.24 inches


Step-to-step explanation:

Given:

The scale factor to model car= \frac{1}{64}\ inches

Thus, if diameter of tire of the actual car is k then diameter of model car =\frac{1}{64}k

Since, the diameter of tire of the model car= 0.41 inches

\\\Rightarrow\frac{1}{64}k=0.41\\\Rightarrow\ k=0.41\times64\\\Rightarrow\ k=26.24\ inches

hence, the diameter of tire of the actual car= 26.24 inches

7 0
3 years ago
USE THE FREQUENCY DISTRIBUTION TO DETERMINE THE FOLLOWING:A) THE TOTAL NUMBER OF OBSERVATIONS.B) THE WIDTH OF EACH CLASS.C) THE
lutik1710 [3]

A) The total number is the sum of all the frequencies

2+5+8+12+11+6=44

Answer: 44

B) The width is (upper limit - lower limit) / 2

(35-21) / 2 = 7

(50-36) / 2 = 7

(65-51) / 2 = 7

(80-66) / 2 = 7

(95-81) / 2 = 7

(110-96) / 2 = 7

Answer: the width is 7

C) The midpoint is the lower limit + the width

36+7=43

Answer: the midpoint is 43

D)The modal is the class with more frequency

In this case 66-80 with 12

Answer: class 66-80

E) We use the width formula

lower limit = 111

width = 7

upper = (width * 2) - lower

upper = (7 * 2) + 111

upper = 125

Answer: class 111-125

4 0
1 year ago
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