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3 years ago

-4x^4 - 3x^3 - 29x^2 - 114 where x= -4

Mathematics

2 answers:

Leno4ka [110]3 years ago

6 0

Answer:

$-1440$

Step-by-step explanation:

------------------------------

Given:

$-4x^4-3x^3-29x^2-114=$

$x=-4$

--------------->>>>

Let's substitute $-4$ for $x$ and solve

$-4(-4)^4-3(-4)^3-29(-4)^2-144=$

Multiply the exponents

$-4(256)-3(-64)-29(16)-144=$

Multiply the parenthesis

$-1024+192-464-144=$

$-832-464-144=$

$-1296-144=$

$=-1440$

------------------------------

Hope this helps.

tatiyna3 years ago

5 0

Answer: -1410

Step-by-step explanation:

Let's start by subbing in -4 for x

$-4x^4 - 3x^3 - 29x^2 - 114\\-4(-4)^4-3(-4)^3-29(-4)^2-114$

Now we can solve

$-4(256)-3(-64)-29(16)-114\\-1024--192-464-114\\-832-464-114\\-1296-114\\-1410$

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