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Varvara68 [4.7K]
3 years ago
8

-4x^4 - 3x^3 - 29x^2 - 114 where x= -4

Mathematics
2 answers:
Leno4ka [110]3 years ago
6 0

Answer:

-1440

Step-by-step explanation:

------------------------------

Given:

-4x^4-3x^3-29x^2-114=

x=-4

--------------->>>>

Let's substitute -4 for x and solve

-4(-4)^4-3(-4)^3-29(-4)^2-144=

Multiply the exponents

-4(256)-3(-64)-29(16)-144=

Multiply the parenthesis

-1024+192-464-144=

-832-464-144=

-1296-144=

=-1440

------------------------------

Hope this helps.

tatiyna3 years ago
5 0

Answer: -1410

Step-by-step explanation:

Let's start by subbing in -4 for x

-4x^4 - 3x^3 - 29x^2 - 114\\-4(-4)^4-3(-4)^3-29(-4)^2-114

Now we can solve

-4(256)-3(-64)-29(16)-114\\-1024--192-464-114\\-832-464-114\\-1296-114\\-1410

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