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sergeinik [125]
3 years ago
8

How do I solve for x?

Mathematics
1 answer:
jeyben [28]3 years ago
8 0
\bf 4x=m(x+y)\implies 4x=mx+my\implies 4x-mx=my
\\\\\\
\stackrel{common~factor}{x(4-m)}=my\implies x=\cfrac{my}{4-m}
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Use the substitution method to solve the system of equations. Choose the correct ordered pair.
balandron [24]
Here you have 2 linear equations and are to solve this system.  Both equations have already been solved for y, so you can set one of them = to the other one:

-2x+11 = -3x+21.

Then 3x-2x = 21 - 11, or         x = 10 (answer)

Find y by subst. x = 10 into either of the given equations.

Solution is then (10, ? )
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3 years ago
Help pls its just math :( <br><br>Ik it sucks I hate math too, pls help tho
Umnica [9.8K]

Answer:

x = - 1

Step-by-step explanation:

Given

- 4(3x - 7) = 40 ( divide both sides by - 4 )

3x - 7 = - 10 ( add 7 to both sides )

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lapo4ka [179]
It would cost somehow less than $1000 and you would know that because 347 students is a large number, but since it hold 44 students in each bus, it’ll take not to long to get to 347. So since each bus is $95, it would at least reach to 700+

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8 0
3 years ago
A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t
Harman [31]

Answer:

The expectation is  E(1 )= -\$ 1

Step-by-step explanation:

From the question we are told that  

     The first offer is  x_1 =  \$ 8000

     The second offer is  x_2 =  \$ 4000

      The third offer is  \$ 1600

      The number of tickets is  n  =  5000

      The  price of each ticket is  p= \$ 5

Generally expectation is mathematically represented as

             E(x)=\sum  x *  P(X = x )

     P(X =  x_1  ) =  \frac{1}{5000}    given that they just offer one

    P(X =  x_1  ) = 0.0002    

 Now  

     P(X =  x_2  ) =  \frac{1}{5000}    given that they just offer one

     P(X =  x_2  ) = 0.0002    

 Now  

      P(X =  x_3  ) =  \frac{5}{5000}    given that they offer five

       P(X =  x_3  ) = 0.001

Hence the  expectation is evaluated as

       E(x)=8000 *  0.0002 + 4000 *  0.0002 + 1600 * 0.001

      E(x)=\$ 4

Now given that the price for a ticket is  \$ 5

The actual expectation when price of ticket has been removed is

      E(1 )= 4- 5

      E(1 )= -\$ 1

4 0
2 years ago
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