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Pachacha [2.7K]
3 years ago
12

Which of the following is a solution to this inequality? y>1/2x+2

Mathematics
1 answer:
Maurinko [17]3 years ago
5 0
The answer is C. (2,3)
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Y + 2 =1/2(x – 3).<br><br> Please help ?!?
Sidana [21]

first, spread the parenthesis. y+2=1/2x-1.5

second, add 1.5 to both sides. y+3.5=1/2x

third, multiply by 2. 2y+7=x

if you are solving for y, do not do the third step, instead, subtract by 3.5. y=x-3.5

hope this helps!

ANSWER: x=2y+7 or y=x-3.5

6 0
3 years ago
Determine whether the function f(x) = -6x^2 - 5 is a quadratic function<br> A) Yes<br> B) No
Yuki888 [10]
The answer is no!!!!!!!
6 0
2 years ago
Solve x: 3x-7 = 5x+13 <br> Solve x: 7-3x = 5x+13
Svetach [21]
First you need to combine like terms
7-3x= 5x+13
step 1 add 3x
7=8x+13
step 2 subteact 13
-6=8x
step 3 divide both sides by two
x=-3/4
4 0
2 years ago
Read 2 more answers
You deposit 2000 in account A, which pays 2.25% annual interest compounded monthly. You deposit another 2000 in account b, which
stellarik [79]
To model this situation, we are going to use the compound interest formula: A=P(1+ \frac{r}{n} )^{nt}
where
A is the final amount after t years 
P is the initial deposit 
r is the interest rate in decimal form 
n is the number of times the interest is compounded per year
t is the time in years 

For account A: 
We know for our problem that P=2000 and r= \frac{2.25}{100} =0.0225. Since the interest is compounded monthly, it is compounded 12 times per year; therefore, n=12. Lets replace those values in our formula:
A=2000(1+ \frac{0.0225}{12} )^{12t}

For account B:
P=2000, r= \frac{3}{100} =0.03, n=12. Lest replace those values in our formula:
A=2000(1+ \frac{0.03}{12} )^{12t}

Since we want to find the time, t, <span>when  the sum of the balance in both accounts is at least 5000, we need to add both accounts and set that sum equal to 5000:
</span>2000(1+ \frac{0.0225}{12} )^{12t}+2000(1+ \frac{0.03}{12} )^{12t}=5000

Now that we have our equation, we just need to solve for t:
2000[(1+ \frac{0.0225}{12} )^{12t}+(1+ \frac{0.03}{12} )^{12t}]=5000
(1+ \frac{0.0225}{12} )^{12t}+(1+ \frac{0.03}{12} )^{12t}= \frac{5000} {2000}
(1.001875)^{12t}+(1.0025 )^{12t}= \frac{5}&#10;{2}
ln(1.001875)^{12t}+ln(1.0025 )^{12t}=ln( \frac{5} {2})
12tln(1.001875)+12tln(1.0025 )=ln( \frac{5} {2})
t[12ln(1.001875)+12ln(1.0025 )]=ln( \frac{5} {2})
t= \frac{ln( \frac{5}{2} )}{12ln(1.001875)+12ln(1.0025 )}
17.47

We can conclude that after 17.47 years <span>the sum of the balance in both accounts will be at least 5000.</span>
5 0
3 years ago
Daniel left a $9 tip for the waiter at a restaurant. If the tip was 15 percent of the bill, how much was the bill?
Pie
Without the tip it was $60. If you are being asked to add the tip it will be $69
5 0
3 years ago
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